Hey gouys I need help on this to plz help mee
1 answer:
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Answer:
Step-by-step explanation:
Probability that a person will not show up is,
P(person not show up)=0.098.
Probability that they will show up is
1-0.098=0.902
P(person will show up)=0.902
Jet passenger seat=18.
a. But is it wise to book 20 passenger seat
If the flight attendant book 20.
We want to know the probability that the two person will not show up.
The probability that the 2 person will not show up out of the 20 is given as
Using binomial distribution
Check attachment for formulas.
P(2 not showing up) =
20C2 • 0.098² • 0.902^20=0.2319
Which is 23.19% that the 2 person will not show up.
b. But is it wise to book 24 passengers for 22 jet seat.
The probability that the 2 will not show up out of the 24 is given as
Using binomial distribution
P(2 not showing up) =
24C2 • 0.098²• 0.902²²=0.2741
Which is 27.41% that the four person will not show up.
c. Probability of no enough seat
For 20 passengers and 18seats on jet
1-0.2319=0.7631.
For 24 passengers and 20 seats on jet
1-27.41=0.7259.
Then, It is not a wise decision because the probability that there are not enough seats on the jet is 0.7259 (72.59%). So, overbooking is an unlikely event.
