Answer:
9* 3 ^ (x-2)
Step-by-step explanation:
g(x) = 3^x
We know a^ (b) * a^(c) = a^ (b+c)
9* 3 ^ (x+2) = 3^2 * 3 ^(x+2) = 3^(2+x+2) = 3^x+4 not equal to 3^x
3*(9^(x+2)) = 3*3^2(x+2) = 3^1 * 3^(2x+4) =3^(2x+4+1) = 3^(2x+5) not equal
9* 3 ^ (x-2) = 3^2 * 3 ^(x-2) = 3^(2+x-2) = 3^x equal to 3^x
3*(9^(x-2)) = 3*3^2(x-2) = 3^1 * 3^(2x-4) =3^(2x-4+1) = 3^(2x-3) not equal
Step-by-step explanation:
my brain couldn't comprehend can u write it down for me real quick like the way it's supposed to be written please
Answer:
-1
Step-by-step explanation:
The mean is the sum of all values divided by the amount of values.
We take the sum of all the numbers:
-3 + -8 + 12 + -15 + 9
-11 + 12 + -15 + 9
1 + -15 + 9
10 + -15
-5
We then divide the sum by how many number we have (we are given 5 numbers):
-5/5 = -1
Therefore, our mean is equal to -1.
We calculate it by multiplying the place value and face value of the digit. For instance: If we consider a number 45. Here the digit 4 is in the tens column.
Answer:
f(x) is shifted to the left 2 units of g(x)
f(x) will not be shifted vertically since we did not add anything to g(x)
Step-by-step explanation:
g(x) = x^2+2
f(x) = g(x+2)
When we shift with h(x+c) it is a horizontal shift
if c>0 it moves it left c units
if c< 0 it moves it right c units
Since c is 2, this is shifted left 2 units
f(x) is shifted to the left 2 units of g(x)
When we shift with h(x)+c it is a vertical shift
if c>0 it moves it up c units
if c< 0 it moves it down c units
f(x) will not be shifted vertically since we did not add anything to g(x)
