No
X would have to equal 6 or greater as if x was 5
5+3 is the same as 8
This is a binomial distribution with n = 5, p = 0.55, q = 1 - 0.55 = 0.45, x = 0, 1, 2, 3
P(x) = nCx p^x q^(n - x)
P(x ≤ 3) = 1 - P(x > 3) = 1 - [P(4) + P(5)]
P(4) = 5C4 x (0.55)^4 x (0.45) = 0.2059
P(5) = 5C5 x (0.55)^5 x 1 = 0.0503
P(x ≤ 3) = 1 - (0.2059 + 0.0503) = 1 - 0.2562 = 0.7438
3 repeating digits are there
Answer:
275 m/s2
Step-by-step explanation:
I know because I had this question in a test and got it correct.
We have to set up 2 different equations if we are to solve for 2 unknowns. The first equation is x = y + 4. One number (x) is (=) 4 more than another (y + 4). Since we have determined that x is larger (cuz it's 4 more than y), when we set up their difference, we are going to subtract y from x cuz x is bigger. The second equation then is

. In our first equation we said that x = y + 4, so let's sub that value in for x in the second equation:

. Expand that binomial to get

. Of course the y squared terms cancel each other out leaving us with 8y + 16 = 64. Solving for y we get that y = 6. Subbing 6 in for y in our first equation, x = 6 + 4 tells us that x = 10. Yay!