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3 years ago

Is 3/8 greater than 3/12

Mathematics

1 answer:

ra1l [238]3 years ago

6 0

3/8>3/12

Solve: The least common denominator is 24

Comparing 9/24 and 6/24:

9/24 > 6/24

therefore

3/8 > 3/12

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Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),

drek231 [11]

Answer:

Step-by-step explanation:

Step one

given the coordinates

ABCD with vertices A(-2,-2), B(-1,3), C(5, 3), and D(4, -2)

AB=(-2,-2),(-1,3)

BC=(-1,3), (5, 3)

CD=(5, 3),(4, -2)

DA=(4, -2),(-2,-2)

The distance between points AB=

$AB= \sqrt (x_2-x_1)^2+(y_2-y_1)^2$

$AB= \sqrt (-1+2)^2+(3+2)^2\\\\AB= \sqrt 1^2+(5)^2\\\\AB= \sqrt26\\\\AB=5.1$

The distance between points BC=

$BC= \sqrt (5+1)^2+(3-3)^2\\\\BC= \sqrt 6^2+(0)^2\\\\BC= \sqrt36\\\\BC=6$

The distance between points CD

$CD= \sqrt (4-5)^2+(-2-3)^2\\\\CD= \sqrt -1^2+(-5)^2\\\\CD= \sqrt26\\\\CD=5.1$

The distance between points DA

$DA= \sqrt (4+2)^2+(-2+2)^2\\\\DA= \sqrt 6^2+(0)^2\\\\DA= \sqrt36\\\\DA=6$

Hence the perimeter = 5.1+6+5.1+6

= 22.2

5 0

2 years ago

The given line passes through the points (-2,-4) and (2,2) What is the equation, in point-slope form, of the line that is parall

Morgarella [4.7K]

Answer:

$(y-1)=\frac{3}{2}(x+3)$

Step-by-step explanation:

The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.

$(y-1)=\frac{3}{2}(x+3)$

3 0

3 years ago

Find the sum of 3b/b 2 and 12/b 2 and express it in simplest form

alexandr1967 [171]

$\frac{3b}{b^{2}} + \frac{12}{b^{2}} = \frac{3b + 12}{b^{2}} = \frac{3(b) + 3(4)}{b^{2}} = \frac{3(b + 4)}{b^{2}}$