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3 years ago

How can I simplify V x 2X

Mathematics

2 answers:

vredina [299]3 years ago

3 0

No you can't because there is no common factor

Marizza181 [45]3 years ago

3 0

No u can't there isn't a common factor

You might be interested in

Find the length of side x in the simplest radical form with a rational denominator.

lisov135 [29]

Answer:

sq root of 6 divided by 2

Step-by-step explanation:

use pythagorean theorem: square of each leg equals the square of the hypotenuse

x squared plus x squared = radical three squared

2x² = 3

x² = $\frac{3}{2}$

x = square root of 3/2

rationalize the denominator to get sq root of 6 divided by 2

6 0

3 years ago

Complete the steps to find the value of . 72° (7x + 24)

stellarik [79]

Answer: x ≈ 6.86°

Step-by-step explanation:

Firstly, set them equal to each other:

(7x + 24) = 72°

Subtract 24 from both sides:

7x = 48°

Divide both sides by 7:

x ≈ 6.857...

This can be rounded to:

x ≈ 6.86°

8 0

3 years ago

Find the value of x of this question

mel-nik [20]

<h3>Let's understand the concept:-</h3>

Here angle B is 90°
So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle
So we use Pythagoras thereon for solution

<h3>Required Answer:-</h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

8 0

3 years ago

Answer for a lot of points!

earnstyle [38]

Given :

ZC = 90°

CD is the altitude to AB.

$\angle$ A = 65°.

To find :

the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> $\angle$ CAB = 65°.

So,

=> $\angle$ ACB + $\angle$ CAB+ $\angle$ ZCBA = 180° (By angle sum Property.)

=> 90° + 65° + $\angle$ CBA = 180°

=> 155° + $\angle$ CBA = 180°

=> $\angle$ CBA = 180° - 155°

=> $\angle$ CBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> $\angle$ CDB = 90°

=> $\angle$ CBD = $\angle$ CBA = 25°.

So,

=> $\angle$ CBD + $\angle$ DCB = 180° (Angle sum Property.)

=> 90° +25° + $\angle$ DCB = 180°

=> 115° + $\angle$ DCB = 180°

=> $\angle$ DCB = 180° - 115°

=> $\angle$ DCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> $\angle$ ADC = 90°

=> $\angle$ CAD = $\angle$ CAB = 65°.

So,

=> $\angle$ ADC + $\angle$ CAD + $\angle$ DCA = 180° (Angle sum Property.)

=> 90° + 65° + $\angle$ DCA = 180°

=> 155° + $\angle$ DCA = 180°

=> $\angle$ DCA = 180° - 155°

=> $\angle$ DCA = 25°

Hence, we get,

$\angle$ DCA = 25°
$\angle$ DCB = 65°
$\angle$ CDB = 90°
$\angle$ ACD = 25°
$\angle$ ADC = 90°.

7 0

3 years ago

What is the distance between point C (3.5,6) and Point A (4.8, 6)

azamat

Answer:

-1/3 and 0

Step-by-step explanation:

3.5-4.8=-1.3

6-6=0

I'm possibly wrong, but I need the points, and brainiest so, sorry if it is wrong.

8 0

3 years ago