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Yakvenalex [24]
3 years ago
15

How can I simplify V x 2X

Mathematics
2 answers:
vredina [299]3 years ago
3 0
No you can't because there is no common factor
Marizza181 [45]3 years ago
3 0
No u can't there isn't a common factor
You might be interested in
Find the length of side x in the simplest radical form with a rational denominator.
lisov135 [29]

Answer:

sq root of 6 divided by 2

Step-by-step explanation:

use pythagorean theorem: square of each leg equals the square of the hypotenuse

x squared plus x squared = radical three squared

2x² = 3

x² =  \frac{3}{2}

x = square root of 3/2

rationalize the denominator to get sq root of 6 divided by 2

6 0
3 years ago
Complete the steps to find the value of .<br> 72°<br> (7x + 24)
stellarik [79]

Answer: x ≈ 6.86°

Step-by-step explanation:

Firstly, set them equal to each other:

(7x + 24) = 72°

Subtract 24 from both sides:

7x = 48°

Divide both sides by 7:

x ≈ 6.857...

This can be rounded to:

x ≈ 6.86°

8 0
3 years ago
Find the value of x of this question ​
mel-nik [20]
<h3><u>Let's</u><u> </u><u>understand</u><u> </u><u>the concept</u><u>:</u><u>-</u></h3>
  • Here angle B is 90°
  • So \triangle ABC and \triangle ABD Are right angled triangle
  • So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

8 0
3 years ago
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
What is the distance between point C (3.5,6) and Point A (4.8, 6)​
azamat

Answer:

-1/3 and 0

Step-by-step explanation:

3.5-4.8=-1.3

6-6=0

I'm possibly wrong, but I need the points, and brainiest so, sorry if it is wrong.

8 0
3 years ago
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