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3 years ago

How can I simplify V x 2X

Mathematics

2 answers:

vredina [299]3 years ago

3 0

No you can't because there is no common factor

Marizza181 [45]3 years ago

3 0

No u can't there isn't a common factor

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The age of the children in kindergarten on the first day of school is uniformly distributed between 4.8 and 5.8 years old. A fir

Kazeer [188]

Answer:

(1) (c) 5.30 years.

(2) (b) 0.289.

(3) (b) 0.80.

(4) (d) 0.50.

(5) (a) 5.25 years.

Step-by-step explanation:

Let X = age of the children in kindergarten on the first day of school.

The random variable X follows a continuous Uniform distribution with parameters a = 4.8 years and b = 5.8 years.

The probability density function function of X is:

$f_{X}(x)=\left \{ {{\frac{1}{b-a}} ;\ a$

(1)

The expected value of a Uniform random variable is:

$E(X)=\frac{1}{2}(a+b)$

Compute the mean of X as follows:

$E(X)=\frac{1}{2}(a+b)=\frac{1}{2}\times (4.8+5.8)=5.3$

Thus, the mean of the distribution is (c) 5.30 years.

(2)

The standard deviation of a Uniform random variable is:

$SD(X)=\sqrt{\frac{1}{12}(b-a)^{2}}$

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{\frac{1}{12}(b-a)^{2}}=\sqrt{\frac{1}{12}\times (5.8-4.8)^{2}}=0.289$

Thus, the standard deviation of the distribution is (b) 0.289.

(3)

Compute the probability that a randomly selected child is older than 5 years old as follows:

$P(X>5)=\int\limits^{5.8}_{5} {\frac{1}{5.8-4.8}}\, dx\\$

$=\int\limits^{5.8}_{5} {1}\, dx\\=[x]^{5.8}_{5}\\=(5.8-5)\\=0.8$

Thus, the probability that a randomly selected child is older than 5 years old is (b) 0.80.

(4)

Compute the probability that a randomly selected child is between 5.2 years and 5.7 years old as follows:

$P(5.2$

$=\int\limits^{5.7}_{5.2} {1}\, dx\\=[x]^{5.7}_{5.2}\\=(5.7-5.2)\\=0.5$

Thus, the probability that a randomly selected child is between 5.2 years and 5.7 years old is (d) 0.50.

(5)

It is provided that a randomly selected child is at the 45th percentile.

This implies that:

P (X < x) = 0.45

Compute the value of x as follows:

$P (X < x) = 0.45$

$\int\limits^{x}_{4.8} {\frac{1}{5.8-4.8}}\, dx=0.45$

$\int\limits^{x}_{4.8} {1}\, dx=0.45$

$[x]^{x}_{4.8}=0.45$

$x-4.8=0.45\\$

$x=0.45+4.8\\x=5.25$

Thus, the age of the child at the 45th percentile is (a) 5.25 years.

6 0

3 years ago

Help help help help Answer please

Ludmilka [50]

Answer:

Mark talked on the phone for 120 minutes.

Step-by-step explanation:

18 - 12 = 6

6 ÷ .05 = 120

6 0

3 years ago

Need help plsssssss help Here are two number machines, A and B.

olga2289 [7]

Answer:

Step-by-step explanation:so I think

You +8×5=40

-4×3=-12

5 0

3 years ago

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Elena is bicycling 9.28 miles to her friend's house. She has already bicycled 3.39 miles. She needs to bicycle m more miles to r

Gnoma [55]

Answer:

m = 5.89

Step-by-step explanation:

hope this helpes~

3 0

3 years ago

A basketball player scored 29 points in a game. The number of three-point field goals the player made was 29 less than three tim

jek_recluse [69]

If you let x represent the number of free throws.
let y represent the number of two-point field goal.
let z represent the number of three-point shots made.

Then the correct system of linear equations is as follows:

x + 2y + 3z = 29 (The total number of points scored is 29.)
z = 3x - 29 (The number of 3-pointers was 29 less than 3 times the number of free throws.)
2y = z + 15 (Twice the number of 2-point shots made was 15 more than the number of 3-pointers.)

Solution:
This basketball player scored 10 points via free throws (10 at 1 point each), 16 points via 8 two-point shots made, and 3 points via 1 three-point shots made. So, in the choice its letter D.

7 0

3 years ago

Read 2 more answers