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zloy xaker [14]
3 years ago
5

Graph the function by making a table of values which table is correct

Mathematics
1 answer:
Talja [164]3 years ago
3 0

It is often more convenient to evaluate a polynomial when it is written is "Horner form."

... f(x) = (((10x -4)x -8)x +3)x -6

The graphs offered can be distinguished by their values of f(1) and f(2), so our table can be a short one.

... f(1) = (((10·1 -4)1 -8)1 +3)1 -6 = -5 . . . . . . . eliminates graph d

... f(2) = (((10·2 -4)2 -8)2 +3)2 -6 = 96 . . . . eliminates graphs a and c

The appropriate choice is b.

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A shopper buys a 100 dollar coat on sale for 20% off. An additional 5 dollars are taken off the sales price by using a discount
koban [17]

Answer:

<u>12.2</u>

Step-by-step explanation:

100 - 20% = 80%, 80% - 5 =  -42, -42 - 8 = <u>-12.2</u>

6 0
3 years ago
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Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
3 years ago
I am so confused right now plz help me
Maksim231197 [3]
You have to remember P.E.M.D.A.S. when doing problems like this.
Drew used PEMDAS so we know he isn't wrong. However, Sam didn't use PEMDAS. She multiplied 2&5 instead of raising 5 to the second. 
The correct answer for Sams' problem would be 30.
Hope this helps! :)
3 0
3 years ago
The ratio of a basketball player's completed free throws to attempted free throws is 4 to 7. if she completed 12 free throws, fi
Artemon [7]
Ratio of the free throws completed to attempted free throws is given to be 4:7. This ratio should be equal to the ratio of the next case. Let x be the number of free throws attempted. The proportion takes a form of,                  
                    (4 completed / 7 attempted) = (12 completed / x attempted)
Solving for x gives x = 21. Thus, the answer is letter c. which is the second among the choices. 
6 0
4 years ago
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Use distributive property to rewrite 10(5+14-3)
Allisa [31]
(10x5)+(10x14)+(10x-3)
50+140-30
160
7 0
3 years ago
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