Answer:
8x+12y<=192
Step-by-step explanation:
Create an inequality to represent Cheryl's situation, where x is the number of 8-ounce jars, and y is the number of 12-ounce jars.
8x+12y<=192
To graph the inequality, rewrite it in slope-intercept form.
8x+12y<=192
12y<=-8x+192
y<=-(2)/(3)x+16
Graph the boundary line as solid, with a y-intercept at (0,16) and a slope -2/3 of. Then, shade the half-plane below the line.
The cost of one bag of Tabitha Tidbits costs $7.00 and cost of one bag of Figaro Flakes costs $5.50
Step-by-step explanation:
Let,
Cost of one bag of Tabitha Tidbits = x
Cost of one bag of Figaro Flakes = y
According to given statement;
3x+4y=43.00 Eqn 1
3x+6y=54.00 Eqn 2
Subtracting Eqn 1 from Eqn 2
![(3x+6y)-(3x+4y)=54.00-43.00\\3x+6y-3x-4y=11.00\\2y=11.00](https://tex.z-dn.net/?f=%283x%2B6y%29-%283x%2B4y%29%3D54.00-43.00%5C%5C3x%2B6y-3x-4y%3D11.00%5C%5C2y%3D11.00)
Dividing both sides by 2
![\frac{2y}{2}=\frac{11}{2}\\y=5.50](https://tex.z-dn.net/?f=%5Cfrac%7B2y%7D%7B2%7D%3D%5Cfrac%7B11%7D%7B2%7D%5C%5Cy%3D5.50)
Putting y=5.50 in Eqn 1;
![3x+4(5.50)=43.00\\3x+22.00=43.00\\3x=43.00-22.00\\3x=21.00](https://tex.z-dn.net/?f=3x%2B4%285.50%29%3D43.00%5C%5C3x%2B22.00%3D43.00%5C%5C3x%3D43.00-22.00%5C%5C3x%3D21.00)
Dividing both sides by 3
![\frac{3x}{3}=\frac{21.00}{3}\\x=7.00](https://tex.z-dn.net/?f=%5Cfrac%7B3x%7D%7B3%7D%3D%5Cfrac%7B21.00%7D%7B3%7D%5C%5Cx%3D7.00)
The cost of one bag of Tabitha Tidbits costs $7.00 and cost of one bag of Figaro Flakes costs $5.50
Keywords: linear equations, elimination method
Learn more about elimination method at:
#LearnwithBrainly
Acute angle i think about 60
Step-by-step explanation:
Here n = 8 (even number)
![\therefore \: \frac{n}{2} = \frac{8}{2} = 4 \\ \\\&\:\: \frac{n}{2} + 1 = 4 + 1 = 5 \\ \\ hence \: \\ median = \frac{ {4}^{th} term + {5}^{th} term}{2} \\ \\ \therefore \: 49 = \frac{x - 1 + x + 1}{2} \\ \\ \therefore \: 49 = \frac{2x}{2} \\ \\ \therefore \: 49 = x \\ \\ \huge \purple { \boxed{\therefore \: x = 49}}](https://tex.z-dn.net/?f=%20%5Ctherefore%20%5C%3A%20%20%5Cfrac%7Bn%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B8%7D%7B2%7D%20%20%3D%204%20%5C%5C%20%20%5C%5C%5C%26%5C%3A%5C%3A%20%20%20%5Cfrac%7Bn%7D%7B2%7D%20%20%2B%201%20%3D%204%20%2B%201%20%3D%205%20%5C%5C%20%20%5C%5C%20hence%20%5C%3A%20%20%5C%5C%20median%20%3D%20%5Cfrac%7B%20%7B4%7D%5E%7Bth%7D%20term%20%2B%20%20%7B5%7D%5E%7Bth%7D%20term%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%2049%20%3D%20%20%5Cfrac%7Bx%20-%201%20%2B%20x%20%2B%201%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%2049%20%3D%20%20%5Cfrac%7B2x%7D%7B2%7D%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%2049%20%3D%20x%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%5Cpurple%20%7B%20%5Cboxed%7B%5Ctherefore%20%5C%3A%20x%20%3D%2049%7D%7D)