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mel-nik [20]
3 years ago
10

I have no idea what the hec this is asking me pls help ;-;

Chemistry
2 answers:
asambeis [7]3 years ago
5 0

Answer:

shut your b word a up

Explanation:

shi idk so shut your b word as up

olya-2409 [2.1K]3 years ago
3 0
I think the answer is B 4.55
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When a jar of coffee is opened, people in all parts of the room soon notice the smell.
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Answer:

Explanation:

because in air the particles are moving very fast and jar of coffee has hot particles which kinetic energy is also more so that's why it's particles move faster and gets mixed with air and smell is coming from far away

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4. Evaluate the information contained in this calculation and complete the
Neporo4naja [7]

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H = mCpT

H = (5kg)( 4.475 kJ/kg-K)(10-0)

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4 years ago
What is/are one of the environmental waste products of nuclear energy?
Alenkinab [10]

D. radioactive isotopes are one of the environmental waste products of nuclear energy.

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3 years ago
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What is the density (g/ml) of a sample of mineral oil . if 250ml has a mass of 0.23kg​
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3 years ago
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Part a cyclohexane has a freezing point of 6.50 ∘c and a kf of 20.0 ∘c/m. What is the freezing point of a solution made by disso
Andrei [34K]

The mathematical expression for the depression in freezing point is given as:

\Delta T_{f}= k_{f}m

where, \Delta T_{f} = depression in freezing point

k_{f} = molal depression constant    (20.0 ^{o}Ckg/mole)

m = molality

Molality is defined as the ratio of number of moles of solute to the kg of the solvent

Number of moles  =\frac{given mass in g}{molar mass}

given mass  of biphenyl solute = 0.925 g

Molar mass of biphenyl  = 154.21 g/mol

Put the values,

number of moles of biphenyl =\frac{0.925 g}{154.21 g/mol}

= 0.0059 mole

Molality =\frac{number of moles of biphenyl solute}{mass of the solvent in kg}

Mass of cyclohexane solvent  = 25.0 g

Convert g into kg: 1 kg = 1000 g

Thus, mass of cyclohexane  = \frac{25.0}{1000}

= 0.025 kg

Now, put the values in the formula of molality:

Molality =\frac{0.0059 mole}{0.025 kg}

= 0.236 mole/kg or 0.236 m.

Calculate the depression in freezing point:

\Delta T_{f}= 20.0^{o}C kg/mole\times 0.236 mole/kg

= 4.72 ^{o}C

Now, \Delta T_{f} = T_{solvent} - T_{solution}

4.72 ^{o}C = 6.50^{o}C - T_{solution}

T_{solution} = 6.50^{o}C- 4.72 ^{o}C

= 1.78^{o}C

Hence, freezing point of the solution is 1.78^{o}C.



4 0
3 years ago
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