Question

Calculate the maximum concentration (in m) of calcium ions (Ca2+ ) in a solution that contains of CO3^2-. The ksp of CaCO3 is?

Answer 1

The maximum concentration (in m) of calcium ions[$Ca^{2+}$] in the given solution is 6.2×$10^{-8}$

The balanced equillibrium equation is ,

$CaCO_{3}$ (s) ↔ $Ca^{2+}$(aq) + $CO_{3} ^{2-}$(aq)

From the reaction equation above, the formula for Ksp:

Ksp = [$Ca^{2+}$][  $CO_{3} ^{2-}$] = 3.4×$10^{-9}$

We know the value for [ $CO_{3} ^{2-}$] , so we can solve for [$Ca^{2+}$]as:

( 3.4×$10^{-9}$) = [$Ca^{2+}$] (0.055)

[$Ca^{2+}$] = 61.8×$10^{-9}$

[$Ca^{2+}$] = 6.2×$10^{-8}$

Therefore, the maximum concentration (in m) of calcium ions[$Ca^{2+}$]  in the given solution is 6.2×$10^{-8}$

Learn more about calcium ions[$Ca^{2+}$] here:

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