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Stella [2.4K]
2 years ago
9

Calculate the maximum concentration (in m) of calcium ions (Ca2+ ) in a solution that contains of CO3^2-. The ksp of CaCO3 is?

Chemistry
1 answer:
KATRIN_1 [288]2 years ago
8 0

The maximum concentration (in m) of calcium ions[Ca^{2+}] in the given solution is 6.2×10^{-8}

The balanced equillibrium equation is ,

CaCO_{3} (s) ↔ Ca^{2+}(aq) + CO_{3} ^{2-}(aq)

From the reaction equation above, the formula for Ksp:

Ksp = [Ca^{2+}][  CO_{3} ^{2-}] = 3.4×10^{-9}

We know the value for [ CO_{3} ^{2-}] , so we can solve for [Ca^{2+}]as:

( 3.4×10^{-9}) = [Ca^{2+}] (0.055)

[Ca^{2+}] = 61.8×10^{-9}

[Ca^{2+}] = 6.2×10^{-8}

Therefore, the maximum concentration (in m) of calcium ions[Ca^{2+}]  in the given solution is 6.2×10^{-8}

Learn more about calcium ions[Ca^{2+}] here:

brainly.com/question/19865131

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sleet_krkn [62]
It is the horizon layer
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4 0
4 years ago
The changing of a substance from a liquid into a vapor or gas is called
sergejj [24]

Answer: Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.

Explanation: Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.

6 0
1 year ago
What is the vapor pressure (in kPa) of ethanol, CH3CH2OH, over a solution which is composed of 18.00 mL of ethanol and 12.55 g o
ladessa [460]

Answer:

The vapor pressure of ethanol in the solution is 10,27 kPa

Explanation:

To obtain the vapor pressure of a solution it is necessary to use Raoult's law:

P_{solution} = X{solvent}P_{0solvent} <em>(1)</em>

The moles of ethanol are:

18,00mL×\frac{0,789g}{1mL}×\frac{1 mol}{46,07g} = 0,3083 mol Ethanol.

Moles of benzoic acid:

12,55 g×\frac{1mol}{122,12g} = 0,1028 mol benzoic acid.

Thus, mole fraction of solvent, X, is:

\frac{0,3083 mol}{0,3083mol+0,1028mol} =<em> 0,7499</em>

Replacing this value in (1):

P_{solution} = 0,7499*13,693kPa = <em>10,27 kPa</em>

<em></em>

I hope it helps!

7 0
3 years ago
If we mix 25 grams of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chlori
erik [133]

Answer:

Theoretical yield of sodium chloride = 14.04 g

Explanation:

Given data:

Mass of sodium bromide = 25 g

Theoretical yield of sodium chloride = ?

Solution:

Chemical equation:

NaBr + KCl  → NaCl  + KBr

Number of moles sodium bromide:

Number of moles = Mass /molar mass

Number of moles = 25.0 g / 102.9 g/mol

Number of moles = 0.24 mol

Now we will compare the moles of NaCl with NaBr  .

                  NaBr         :               NaCl

                    1               :               1

                 0.24           :            0.24

Theoretical yield of sodium chloride:            

Mass  = moles × molar mass

Mass = 0.24 mol ×  58.5 g/mol

Mass =  14.04 g

7 0
3 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
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