Answer:
We have a small circle, that is dilated by a factor of 5/3 creating a larger circle.
If the smaller circle has a diameter D, then after the dilation, the larger circle will have a diameter equal to: (5/3)*D
We know that the area of the larger circle is:
A = 100*pi cm^2.
And the area of a circle of diameter d, is:
a = pi*(d/2)^2
knowing that the diameter of the large circle is (5/3)*D, we can find the value of D.
A = pi*( (5/3)*D/2)^2 = 100*pi cm^2
let's solve this for D:
pi*( (5/3)*D/2)^2 = 100*pi cm^2
( (5/3)*D/2)^2 = 100 cm^2
( (5/3)*D/2) = √(100 cm^2) = 10cm
D/2 = (3/5)*10cm
D = 2*(3/5)*10cm = 12cm.
Then the area of the smaller circle will be:
a = pi*(D/2)^2 = pi*(12cm/2)^2 = pi*(6cm)^2 = pi*36 cm^2
and pi = 3.14
a = pi*36 cm^2 = 3.14*36cm^2 = 113.04 cm^2
Volume of a cylinder = PI x r^2 x H
r = 4 so r^2 = 4^2 = 16
h = 3
Volume = 3.14 x 16 x 3 = 150.72 ft^3
it doesn't say how to round the answer so you may need to round it
Answer:
5.3
Step-by-step explanation:
-2r+3s
Let r=-8.2 s=-3.7
-2(-8.2) +3(-3.7)
16.4-11.1
5.3
A) N + D = 30
B) .05N + .1D = 2.20
Multiplying equation A by -.05
A) -.05N -.05D = -1.50 then adding it to B
B) .05N + .1D = 2.20
.05D = .70
Dimes = 14
Nickels = 30 -14 = 16
