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LenKa [72]
3 years ago
7

A rocket releases a satellite into orbit around Earth, The satellite travels at 2000 m/s in 25 seconds. What is the acceleration

?
Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

80

Step-by-step explanation:

The formula to calculate speed is s=d/t. If the distance is 2,000 m/s and the time is 25 seconds, you plug in the numbers into the formula for speed. 2,000/25=80

The satellite's acceleration (speed) is 80.

(I'm not exactly sure what the unit should be for the answer 80, but...) I hope this helps and have a great day!! :3

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The following question has two parts. First, answer part A. Then, answer part B.
Arturiano [62]

Answer:

  Part A:  13.2

  Part B:  see below

Step-by-step explanation:

<u>Part A</u>:

13.245 rounded to tenths is 13.2

<u>Part B</u>:

The rule is ...

  <em>Add 1 in the number place you're rounding to if the digit to its right is 5 or more. Drop (or zero) all digits to the right of the place you're rounding to.</em>

Here, the digit to the right of the tenths place is 4, so no action is taken other than dropping digits to the right of the tenths place.

3 0
3 years ago
Use synthetic division to divide (x^ 3 + x^ 2 – 40x – 4) ÷ (x – 6)
Marina CMI [18]
The answer is C.

Hope this helps!!

7 0
3 years ago
Read 2 more answers
For a certain commodity the supply equation is given by S = 2p + 5 At a price of $1, there is a demand for 19 units of the commo
slava [35]

Answer:

The demand equation is: D=-4p+23

Step-by-step explanation:

To get started, we should keep in mind that the market price (p=3) occurs when supply equals demand ,therefore when p=3

S=2(3)+5=11

Thus, when p=3 D=11 and, according to the problem  when p=1 D=19.

We already know two points on the demand curve. Great!

The demand equation is linear, so it has form D=bp+c.

The variable b is the slope of  the demand linear equation . It can be computed through the formula

b=\frac{y2-y1}{x2-x1}.  equation 1

Substituting the two points (3,11) and (1,19) on equation 1.

b=\frac{19-11}{1-3} =\frac{8}{-2}

b=-4

Now we can find the value of  intercept of the demand equation c trough point-slope form y-y1=b(x-x1).

We can use any of the points. Let's take (3,11) and write in point-slope :

y-11=-4(x-3)

y=-4x+11+12

y=-4x+23

Rewrite the linear equation according our variables D and p

D=-4P+23

Finally we found the demand equation !

5 0
4 years ago
What is the equation of the line that passes through the point (6,14) and is parallel to the line with the following equation? y
Gekata [30.6K]

Answer:

y=\displaystyle-\frac{4}{3}x+22

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept
  • Parallel lines always have the same slope (<em>m</em>)

<u>Determine the slope (</u><em><u>m</u></em><u>):</u>

<u />y=\displaystyle-\frac{4}{3}x -1<u />

The slope of the given line is \displaystyle-\frac{4}{3}, since it is in the place of <em>m</em> in y=mx+b. Because parallel lines always have the same slope, the slope of a parallel line would also be \displaystyle-\frac{4}{3}. Plug this into y=mx+b:

y=\displaystyle-\frac{4}{3}x+b

<u>Determine the y-intercept (</u><em><u>b</u></em><u>):</u>

y=\displaystyle-\frac{4}{3}x+b

To find the y-intercept, plug in the given point (6,14) and solve for <em>b</em>:

14=\displaystyle-\frac{4}{3}(6)+b\\\\14=-8+b\\b=22

Therefore, the y-intercept of the line is 22. Plug this back into y=\displaystyle-\frac{4}{3}x+b:

y=\displaystyle-\frac{4}{3}x+22

I hope this helps!

5 0
3 years ago
What is the value of x ? 6.75 + 3/8x = 13 1/4
Bad White [126]

Let's solve your equation step-by-step.

6.75+38x=1314

Step 1: Simplify both sides of the equation.

38x+6.75=534

Step 2: Subtract 6.75 from both sides.

38x+6.75−6.75=534−6.75

38x=132

Step 3: Multiply both sides by 8/3.

(83)*(38x)=(83)*(132)

x=523

Answer:

x=1713

7 0
3 years ago
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