Answer:
7 ( 3x + 5y) = <u>21x+35y</u>
<u>Step-by-step explanation:</u>
<u>Step 1 : </u> apply the distributive law. <u>("the law relating the operations of multiplication and addition")</u>
<em>a ( b + c ) = ab + ac</em>
7 ( 3x + 5y) = 7 x 3x + 7 x 5y
<u>Step 2 : simplify </u>7 x 3x + 7 x 5y
So, the answer is <u>21x+35y</u>
Brainliest? :D and hope this helps!
Learn more about Distributive Property:
<u>brainly.com/question/2807928</u>
Answer:
I'm guessing 170 miles.
Sry if i'm wrong, I tried my best.
It'll also make me happy if you would subscribe to my channel Yaya Playz 23, and my friends BonheurPlaysGames!!! and Sagesse Games, there small YTers as well. Thank you!
Answer:
<em></em>
<em>The team must win 2 games to have a win : loss ratio o 2.</em>
Step-by-step explanation:
- <u>Ratio win : loss, r</u>:
r = total wins / total losses
Call n the number of new wins:
Tw =number of wins until so far + number of new win = 6 + n
Tl = number of losses so far + number of new losses = 4 + 0 = 4
r = 2 ⇒ Tw / Tl = (6 + n) / 4 = 2
Solve for n:
- (6 + n ) = 4 × 2
- 6 + n = 8
- n = 8 - 6
- n = 2
Hence,<em> the team must win 6 more games.</em>
- <u>Verification</u>: (6 + 2 ) / 4 = 8 / 4 = 2, which is the target ratio.
There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
_____
C(n,k) = n!/(k!(n-k)!)
t=D/r
Divide r by both sides to get t by itself.