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lutik1710 [3]
2 years ago
9

Please help me find the area of this irregular shape.

Mathematics
1 answer:
ANTONII [103]2 years ago
6 0

Answer:

23 Cm(2)

Step-by-step explanation:

Sincerest Apologies if it is incorrect

if it's not 23 it may be:

26 Cm(2)

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Asked on December 20, 2019 by

Ziya Vïvəķ

A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

2

56

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

2

h=32×22×14 cm

3

7

22

×(28)

2

×h=9856 cm

h=

22×784

9856×7

cm

h=4 cm

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3 years ago
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find the probability exactly 3 successes in 6 trials of a binomial experiment in which the probability of success if 50%. round
Dennis_Churaev [7]

Answer:

Hence, the probability of exactly 3 successes in 6 trials of a binomial experiment round to the nearest tenth of a percent is:

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Step-by-step explanation:

The probability of getting exactly k successes in n trials is given by the probability mass function:



{\displaystyle P(k;n,p)=P(X=k)={\binom {n}{k}}p^{k}(1-p)^{n-k}}

Where p denotes the probability of success.

We are given that  the probability of success if 50%.

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also form the question we have:

k=3 and n=6.

Hence the probability of exactly 3 successes in 6 trials is:


{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{3}(1-\dfrac{1}{2})^{6-3}}


{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{3}(\dfrac{1}{2})^{3}}

{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{6}

\binom {6}{3}=20

Hence,

{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)=20\times (\dfrac{1}{2})^6=\dfrac{5}{16}

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8 0
3 years ago
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