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lutik1710 [3]
3 years ago
9

Please help me find the area of this irregular shape.

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

23 Cm(2)

Step-by-step explanation:

Sincerest Apologies if it is incorrect

if it's not 23 it may be:

26 Cm(2)

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Find the exact values of sin(u/2) cos(u/2) and tan(u/2) given sin u=24/25 and pie/2 < u < pie
vlada-n [284]

Recall the double/half angle formulas:

\cos^2\dfrac x2=\dfrac{1+\cos x}2

\sin^2\dfrac x2=\dfrac{1-\cos x}2

We're given \sin u=\frac{24}{25}, and since u is between π/2 and π, we expect \cos u to be negative. So from the Pythagorean identity, we find

\sin^2u+\cos^2u=1\implies\cos u=-\sqrt{1-\sin^2u}=-\dfrac7{25}

Also, we know \frac u2 will fall between π/4 and π/2, so both \sin\frac u2 and \cos\frac u2 will be positive. Then we find

\cos\dfrac u2=\sqrt{\dfrac{1+\cos u}2}=\dfrac35

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and it follows that

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8 0
4 years ago
Please help!! Due really soon!
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9514 1404 393

Answer:

  f(x) = 6x +1

Step-by-step explanation:

Differences in x-values (first row) are 1, 1, 1.

Differences in y-values (second row) are 6, 6, 6.

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Using the first point in the form ...

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we have ...

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3 years ago
jon buys packages of pens for $5 each. identify the independent and dependent variables in the situation
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This is simply a matter of pluggin in the method, so let's do it shall we?

It wants you to put the a third of each number, so you'll divide each number by three to get what the third is!

VISUAL REPRESENTATION:

12÷3 = 4

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