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3 years ago

Can someone please help me with this!!

Mathematics

1 answer:

Aloiza [94]3 years ago

8 0

Answer:

$407 yd^{2}$

Step-by-step explanation:

first find the area of the rectangle, which would be $16*13 = 208$ yd²

then find the arc length of the sector, which is about 30.6yd

use the arc length to find the area of the sector, which is about 199.09yd²

add together the area of the rectangle and sector:

199.09 + 208 ≈ 407

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Simplify the Expression

ivann1987 [24]

Answer:

11x+7

Step-by-step explanation:

This is because, in order to simplify, first you need to distribute the 2 into the x+5. So, you get 2x+10. Then you get 9x-3+2x+10. The 9x and 2x combine to get 11x. The -3+10 combine to get 7. So you have 11x+7.

8 0

3 years ago

Read 2 more answers

Which function represents g(x), a reflection of f(x) =

Ede4ka [16]

Answer:

Option A.

Step-by-step explanation:

Note: The given function should be $f(x)=\dfrac{2}{5}(10)^x$ instead of $f(x)=(10)^x$ .

Consider the given function is

$f(x)=\dfrac{2}{5}(10)^x$

We need to find the function which represents a reflection of f(x) across the x-axis.

If a function f(x) is reflected across the x-axis, then the new function is

$g(x)=-f(x)$

Using this rule, we get

$g(x)=-\dfrac{2}{5}(10)^x$ $[\because f(x)=\dfrac{2}{5}(10)^x]$

Therefore, the correct option is A.

6 0

3 years ago

Solve for the roots in simplest form by completing the square 6x^2+120x+2070=0

Kitty [74]

Answer:

Step-by-step explanation:

First, we can divide out the common factor, 6

$6x^2 + 120x + 2070 = 0\\x^2 + 20x + 345 = 0\\$

Now we complete the square

$(x^2 + 20x + (\frac{20}{2})^2) + 345 - (\frac{20}{2})^2\\(x^2 + 20x + 100) + 345 - 100\\(x+10)^2 + 245\\$

$(x+10)^2 = -245\\x + 10 = \sqrt{-245}\\x = i\sqrt{245} - 10\\x = -10 \pm i\sqrt{245}$

8 0

3 years ago

PLEASE HELPPP!!!! Describe the graph using both set-builedr notation and interval notation.

lutik1710 [3]

Answer:

See below

Step-by-step explanation:

The inequality in the picture is the line to the left from 15

Set builder notation

{x | x < 15}

Interval notation

(-oo, 15)

8 0

3 years ago

Content - Common

balu736 [363]

9514 1404 393

Answer:

∠BCA = 30°
∠FHC = 125°
∠A = 45°
∠GBC = 75°
arc EBC = 260°

Step-by-step explanation:

Angle BCA intercepts arc FB, so is half its measure: 60°/2 = 30°.

Angle FHC is half the sum of the angles intercepted by its chords: (60°+150°+40°)/2 = 125°.

Angle A is half the difference of the arcs it intersects: (150° -60°)/2 = 45°.

Angle GBC is half the measure of the arc it intercepts: 150°/2 = 75°.

arc EBC is the sum of arcs EF, FB, and BC: 50° +60° +150° = 260°.

5 0

3 years ago