<span>The best and most correct answer among the choices provided by the question is the first choice. A decrease on the pine trees would decrease the number of the woodpeckers. <span>I hope my answer has come to your help. God bless and have a nice day ahead</span></span><span>
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Answer:
malai tah navatako awsatha haha halka ramaila lo hoho vadragol
The right answer is the activation energy.
The catalyst increases the reaction rate by introducing new reaction paths (mechanism), and lowering its activation energy, or activation Gibbs free energy. By doing this it can increase the speed, or lower the temperature of the reaction. It is important to note that the catalyst does not alter the total Gibbs free energy of the reaction which is a system state function and therefore has no effect on the equilibrium constant.
<span>d. neither of these will cross a plasma membrane.
Glucose cannot diffuse across a plasma membrane as it is polar. Since the question doesn't specify the type of diffusion, simple diffusion is assumed.
If you count facilitated diffusion, then A is the answer.</span>
Answer:
The enzyme is the pyruvate kinase
Explanation:
The designated enzyme can only grow in pyruvate or in ethanol. They are said to be in anaerobic conditions. If the end product of glycolysis is pyruvate and the enzyme that transforms phosphoenol pyruvate into pyruvate is called pyruvate kinase. In a reaction under anaerobic conditions, the pyruvate is transformed into ethanol. So if the pyruvate kinase enzyme is mutated, pyruvate cannot be transformed into ethanol and Saccharomyces cerevisiae could not survive in that medium.
