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NikAS [45]
3 years ago
8

Which of the following remote access security technologies performs authentication through a three-way handshake (that is, chall

enge, response, and acceptance messages) between a server and a client, where the three-way handshake allows a client to be authenticated without sending credential information across a network?
CHAP
Computers and Technology
1 answer:
levacccp [35]3 years ago
7 0

Answer:

CHAP

Explanation:

CHAP allows a client to be authenticated without sending credential information across a network.

You might be interested in
Write the Number class that can be used to test if the number is odd, even, and perfect. A perfect number is any number that is
egoroff_w [7]

Answer:

Explanation:

The following code is written in Python. It creates a class that takes in one ArrayList parameter and loops through it and calls two functions that check if the numbers are Perfect, Odd, or Even. Then it goes counting each and printing the final results to the screen.

class NumberAnalyzer:

   def __init__(self, myArray):

       perfect = 0

       odd = 0

       even = 0

       for element in myArray:

           if self.isPerfect(element) == True:

               perfect += 1

           else:

               if self.isEven(element) == True:

                   even += 1

               else:

                   odd += 1

       print("# of Perfect elements: " + str(perfect))

       print("# of Even elements: " + str(even))

       print("# of Odd elements: " + str(odd))

   def isPerfect(self, number):

       sum = 1

       i = 2

       while i * i <= number:

           if number % i == 0:

               sum = sum + i + number / i

           i += 1

       if number == sum:

           return True

       else:

           return False

   def isEven(self, number):

       if (number % 2) == 0:

           return True

       else:

           return False

6 0
2 years ago
How to upgrade brainly membership
rjkz [21]

Answer:

Go on account settings, go to subscription, and upgrade.

Explanation:

7 0
3 years ago
Read 2 more answers
How were images captured before the invention of the camera?
xeze [42]

Answer:

The British inventor Fox Talbot produced his first successful photographic images in 1834, without a camera, by placing objects onto paper brushed with light-sensitive silver chloride, which he then exposed to sunlight.

Explanation:

5 0
2 years ago
For this lab you will write a class to create a user-defined type called Shapes to represent different shapes, their perimeters
maw [93]
<h2>Answer:</h2>

<u />

========= Shape.java  ===========

//import the Scanner class

import java.util.Scanner;

public class Shape{

   //required fields

  private String shape;

   private double area;

   private double perimeter;

   //default constructor

  public Shape(){

       this.shape = "unknown";

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //constructor with one parameter

   public Shape(String shape){

       this.setShape(shape);

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //accessors and mutators

  public void setShape(String shape){

       this.shape = shape;

   }

  public String getShape(){

       return this.shape;

   }

   public double getPerimeter(){

       return this.perimeter;

   }

  public double getArea(){

       return this.area;

   }

  public void setPerimeter(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.perimeter = 2 * 3.142 * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.perimeter = 2 * (width + height);

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.perimeter = 4 * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

   }

   public void setArea(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.area = 3.142 * radius * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.area = width * height;

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.area = height * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

   }

   //Own methods

   //1. Method to show the properties of a shape

   public void showProperties(){

       System.out.println();

       System.out.println("The properties of the shape are");

       System.out.println("Shape : " + this.getShape());

       System.out.println("Perimeter : " + this.getPerimeter());

       System.out.println("Area : " + this.getArea());

   

   }

   //2. Method to find and show the difference between the area and perimeter of a shape

   public void getDifference(){

       double diff = this.getArea() - this.getPerimeter();

       System.out.println();

       System.out.println("The difference is " + diff);

   }

}

========= ShapeTest.java  ===========

import java.util.Scanner;

public class ShapeTest {

   public static void main(String [] args){

       Scanner scanner = new Scanner(System.in);

       // create an unknown shape

       Shape shape_unknown = new Shape();

       //get the shape

       System.out.println("The shape is " + shape_unknown.getShape());

       //set the area

       shape_unknown.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_unknown.getArea());

       //set the perimeter

       shape_unknown.setPerimeter(scanner);

       //get the perimeter

       System.out.println("The perimeter is " + shape_unknown.getPerimeter());

       // create another shape - circle

       Shape shape_circle = new Shape("circle");

       //set the area

       shape_circle.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_circle.getArea());

       //set the perimeter

       shape_circle.setPerimeter(scanner);

       //get the area

       System.out.println("The perimeter is " + shape_circle.getArea());

       //get the properties

       shape_circle.showProperties();

       //get the difference between area and perimeter

       shape_circle.getDifference();

   }

}

<h2>Sample output:</h2>

The shape is unknown

You must define a shape first before calculating area

The area is 0.0

You must define a shape first before calculating perimeter

The perimeter is 0.0

Enter the radius of the circle

>> 12

The area is 452.448

Enter the radius of the circle

>> 12

The perimeter is 452.448

The properties of the shape are

Shape : circle

Perimeter : 75.408

Area : 452.448

The difference is 377.03999999999996

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code. Please go through the code for more explanations. For better formatting, the sample output together with the code files have also been attached to this response.

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
57aa40cd91dceaa5454e65fc5d209315.png
5 0
3 years ago
Suppose there are two ISPs providing WiFi service in a café. Each ISP operates its own AP and has its own IP address block. If b
Alinara [238K]

Answer:

As a design rule, access points within range of each other should be set to channel frequencies with minimal signal overlap. Users will find that roaming doesn’t work well, and performance will degrade because of interference between access points.

Explanation:

8 0
3 years ago
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