12:21 is the correct answer
Answer:
for me personally, it would help if the items were rearranged with like items, for example: snow, sleet, rain, and hail would go together.
so the list should look something like this:
<u>weather conditions</u>
<u>fruits</u>
- strawberry
- banana
- apple
- orange
<u>sports</u>
- football
- soccer
- tennis
- rugby
hope i helped <3 have a nice day
Answer:
A varying infrastructure.
Explanation:
The competitive pressure it creates for multinational companies in the industry is one of difference in infrastructure because different technical standards are found in different parts of the world.
For instance, A technical standard known as Global Systems for Mobile (GSM) is common in Europe, and an alternative standard, Code Division Multiple Access (CDMA), is more common in the United States and parts of Asia.
Consequently, equipment designed for GSM will not work on a CDMA network and vice versa as a result of varying infrastructure, so companies would be innovative in order to improve on their products.
The meaning of mesh topology is that it is a type of networking that is made up of the fact that all its nodes do work together to share data amongst each other.
<h3>What is meant by mesh topology?</h3>
Mesh topology is a kind of networking that is said to be where the full nodes do act in a form of a cooperation so that they can be able to share or distribute data among themselves.
Note that this topology was said to be first seen or developed in about an approximate of about 30+ years ago and it is one that is often used in military applications and now it is seen to be used in home automation, smart HVAC control, and others.
Hence, The meaning of mesh topology is that it is a type of networking that is made up of the fact that all its nodes do work together to share data amongst each other.
Learn more about mesh topology from
brainly.com/question/14879489
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Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
