Answer: 240 minutes, 20 cups, 4000 pounds
<u>Step-by-step explanation:</u>
Use the following conversions:
1 hour = 60 minutes
2 cups = 1 pint
2 pints = 1 quart
1 ton = 2000 pounds
3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
They are all true None are false
Answer:
Let "x" be the number of people who can go to the amusement park.
So we have: 19 + 14x ≤ 180. This inequality basically means that the parking cost plus the cost of the tickets for every person cannot cost more than 180 dollars.
Solving this inequality, we get:
19 + 14x ≤ 180
14x ≤ 161
x ≤ 11.5
Obviously, we know that we can't have "half" a person, so the most people who can come to the amusement park would be 11 people, and the answer would be: x ≤ 11
Hope this helps!
To evaluate the probability that a randomly selected day will be between 28 and 34 minutes we proceed as follows:
P(28<x<34)
First we evaluate the z-score for the above values:
z=(x-σ)/μ
μ=26.7
σ=5.1
when:
x=28
z=(28-26.7)/5.1
z=0.26
P(z<0.26)=0.6026
when x=34
z=(34-26.7)/5.1
z=1.43
P(z<1.43)=0.9236
hence:
P(28<x<34)=0.9236-0.6026=0.321~32.1%
