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murzikaleks [220]
3 years ago
10

Can someone please help me

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0
You multiply 6ftx20ft then add 1 to it to get your answer
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Somebody help pls I need help with this
alisha [4.7K]

Answer:

Step-by-step explanation:140

7 0
3 years ago
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How many solutions does the equation −6a + 6a + 5 = 8 have? One Two No solution Infinite solutions
umka21 [38]
<span>−6a + 6a + 5 = 8 
5 = 8  False

So, </span><span>No solution.</span>
5 0
3 years ago
Maya bought 6 CDs that were each the same price. Including sales tax, she paid a total of $97.20. Of that total, $5.40 was tax.
uysha [10]

Answer:

Each CD was $15.30.

Step-by-step explanation:

97.20-5.40= 91.80 => 91.80/6=  15.30

8 0
3 years ago
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Suppose you are given either a fair dice or an unfair dice (6-sided). You have no basis for considering either dice more likely
hoa [83]

Answer: Our required probability is 0.83.

Step-by-step explanation:

Since we have given that

Number of dices = 2

Number of fair dice = 1

Probability of getting a fair dice P(E₁) = \dfrac{1}{2}

Number of unfair dice = 1

Probability of getting a unfair dice  P(E₂) = \dfrac{1}{2}

Probability of getting a 3 for the fair dice P(A|E₁)= \dfrac{1}{6}

Probability of getting a 3 for the unfair dice P(A|E₂) = \dfrac{1}{3}

So, we need to find the probability that the die he rolled is fair given that the outcome is 3.

So, we will use "Bayes theorem":

P(E_1|A)=\dfrac{P(E_1)P(A|E_1)}{P(E_1)P(A|E_1)+P(E_2)P(A|E_2)}\\\\(E_1|A)=\dfrac{0.5\times 0.16}{0.5\times 0.16+0.5\times 0.34}\\\\P(E_1|A)=0.83

Hence, our required probability is 0.83.

8 0
3 years ago
HELPPPPPPP!!!!! PLEASEEEE!!!!
maksim [4K]

Answer:x=1012

Step-by-step explanation:

5 0
2 years ago
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