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murzikaleks [220]
3 years ago
10

Can someone please help me

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0
You multiply 6ftx20ft then add 1 to it to get your answer
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PLEASE HELP ASAP!!!!! a simulation by tossing a coin to model whether these puppies will be male or female. • Let heads (H) = fe
weeeeeb [17]

Answer:

7/10 or 70%

Step-by-step explanation:

There has to be at least two T in each result of the simulation. This means you can also have 3 T's and 4 T's in the result.

These are the results that qualify as having at least two T's.

1. TTTT, 2. TTTT, 3. THTH, 4. HTTT, 5. TTTT, 7. HTHT, 9. THTH

That is 7 out of the 10 results which is 7/10 or 70%

3 0
2 years ago
What is the solution to the equation below?<br><br><br><br> 0.5n = 6
Tcecarenko [31]

It's 12 because if you divide 6 by 0.5 you should get 12, so basically use the opposite operation.

Hope that helps!

3 0
3 years ago
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
3 years ago
in a 30°-60°-90° triangle, the ( blank) is the (blank) the length of the ( blank) while the longer leg is ( blank) times the len
levacccp [35]

Answer:

16

Step-by-step explanation:

4 0
3 years ago
Tammy did a survey to answer the following question:
Mariulka [41]
If all students scored the same the score of each student would be 4.5.
4 0
3 years ago
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