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kirza4 [7]
3 years ago
7

LK is tangent to circle J at point K. Circle J is shown. Line segment J K is a radius. Line segment K L is a tangent that inters

ects at point K. A line is drawn from point L through a point on the circle to the center point J. The length of the radius is r, the length of K L is 11, and the length of the line segment from point L to the point on the circle is 6. What is the length of the radius?
Mathematics
2 answers:
zmey [24]3 years ago
6 0

Answer:

i think it is 66

Step-by-step explanation:

Lera25 [3.4K]3 years ago
3 0

Answer:__________

B: 85/12

You might be interested in
X^3+x²-36 Find all real zeros.
Harman [31]

Answer: x=3

Step-by-step explanation:

To find the zeros, you want to first factor the expression.

x³+x²-36

(x-3)(x²+4x+12)

Now that we have found the factors, we set each to 0.

x-3=0

x=3

Since x²+4x+12 cannot be factored, we can forget about this part.

Therefore, the zeros are x=3. You can check this by plugging the expression into a graphing calculator to see the zeros.

4 0
3 years ago
Please help me!! I really need it (:
klasskru [66]

it is a linear equation

 if you take the negative of x and subtract 1 you get Y

 so the answer is A

5 0
3 years ago
Historical data for a local manufacturing company show that the average number of defects per product produced is 2. In addition
charle [14.2K]

Answer:

The probability that there will be a total of 7 defects on four units  is 0.14.

Step-by-step explanation:

A Poisson distribution describes the probability distribution of number of success in a specified time interval.

The probability distribution function for a Poisson distribution is:

P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}, x=0,1,2,3,...

Let <em>X</em> = number of defects in a unit produced.

It is provided that there are, on average, 2 defects per unit produced.

Then in 4 units the number of defects is, (2\times4)=8.

Compute the probability of exactly 7 defects in 4 units as follows:

P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}\\P(X=7)=\frac{e^{-8}8^{7}}{7!}\\=\frac{0.0003355\times2097152}{5040}\\ =0.1396\\\approx0.14

Thus, the probability of exactly 7 defects in 4 units is 0.14.

8 0
3 years ago
What is equivalent to 3(5-2i)?
Vikki [24]

Answer:

Step-by-step explanation:

One equivalent can be obtain by distributing multiplication with 3 over subtraction 5-2i

3(5-2i) =

3·5 -3·2·i =

15 -6i or -6i +15

5 0
2 years ago
What is 2/4 + 4/5 - 7/10 ? Please help
Radda [10]
Make sure they have all common denominators
\frac{2}{4} + \frac{4}{5} - \frac{7}{10}

\frac{2}{4} * \frac{5}{5} = \frac{10}{20}

\frac{4}{5} * \frac{4}{4} = \frac{16}{20}

\frac{7}{10} * \frac{2}{2} = \frac{14}{20}

\frac{10}{20} + \frac{16}{20} - \frac{14}{20}

Add \frac{10}{20} + \frac{16}{20} = \frac{26}{20}
\frac{26}{20} - \frac{14}{20} = \frac{12}{20}

To simplify, you must find the largest common factor which 4
In \frac{12}{20}
12÷4=3 and 20÷4=5

The answer is \frac{3}{5}
7 0
3 years ago
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