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alexgriva [62]
3 years ago
15

What is the combined weight of the 1/2lb bags

Mathematics
1 answer:
PtichkaEL [24]3 years ago
7 0
2 I think that is the answer
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Can anyone please help me with question need help please ​
Ivanshal [37]

Step-by-step explanation:

there is no reason in maths only the method

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3 years ago
What is the slope of the line?<br> 3x-4y=7
Vinvika [58]

Answer:

3/4

Step-by-step explanation:

3x - 4y = 7.....subtract 3x from both sides

-4y = -3x + 7 ...now we divide both sides by -4

(-4/-4)y = (-3/-4)x + (-7/4)...simplify

y = 3/4x - 7/4

y = mx + b

y = 3/4x - 7/4.....so the number in the m position is 3/4 <== ur slope

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3 years ago
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iragen [17]
Number 1 is 4 radical 10

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3 years ago
I need help plz<br> find the constant rate
iragen [17]

Answer:

- 5 °F/h

Step-by-step explanation:

the constant rate = slope = rise / run = -5/1 = - 5 °F/h

4 0
3 years ago
A particle, initially at rest, moves along the x-axis such that its acceleration at time t &gt; 0 is given by a(t) = 6cos(t). At
Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

The particle starts at rest, so v(0)=0, and we have

v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t

Then the position function is

x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du

with x(0)=6, so

x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t

b. The particle is at rest whenever v(t)=0; this happens for

6\sin t=0\implies \sin t=0\implies t=n\pi

where n is any integer.

3 0
3 years ago
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