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stich3 [128]
3 years ago
6

PLZZZZZ NEED HELP!!!!!!

Mathematics
1 answer:
zzz [600]3 years ago
3 0
If u need help with checking if ur solution is correct use desmos to graph the equations and find the point of intersection

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Solve this equation using a common base
GrogVix [38]

Answer:

Step-by-step explanation:

1. 3x - 7 = 5 - x

   4x = 12

    x = 3

2. 6x + 4 = 2

   6x = -2

   x = -1/3

6 0
2 years ago
Find dy/dx for 4 - xy = y^3
storchak [24]

Answer:

\frac{dy}{dx}=-\frac{y}{3y^2+x}

Step-by-step explanation:

4-xy=y^3

dy/dx=?

\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}

Solving for dy/dx: Addind x dy/dx both sides of the equation:

-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}

Common factor dy/dx on the right side of the equation:

-y=(3y^2+x)\frac{dy}{dx}

Dividing both sides of the equation by 3y^2+x:

\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}

7 0
3 years ago
Javier and Kyle work installing windows and can earn extra money by installing doors. Last week, Javier earned $56 more than Kyl
julia-pushkina [17]

Answer: it would be A hope this helps


Step-by-step explanation:


8 0
3 years ago
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Gre4nikov [31]
Oooooffffffff im pretty positive that this is true

4 0
3 years ago
Sam, Jessie, and Emma go out for burgers. The total cost is $21.39. How much will each person pay if they split the cost equally
Nadusha1986 [10]

Answer:

$7.13

Step-by-step explanation:

There is 3 people and they need to SPLIT the cost. Split means divide in this situation. So, divide 21.39 by 3 and you should get 7.13.

4 0
3 years ago
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