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3 years ago

PLZZZZZ NEED HELP!!!!!!

Mathematics

1 answer:

zzz [600]3 years ago

3 0

If u need help with checking if ur solution is correct use desmos to graph the equations and find the point of intersection

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Find the mean of each data set.<br> 1.9, 10, 11, 16, 12, 12,14

igor_vitrenko [27]

Answer:

Add all the values up and divide by 7 ( as there are 7 values in the data set)

Step-by-step explanation:

1.9 + 10 + 11 + 16 + 12 + 12 + 14 = 76.9

If you divide by 7, you will get 10.9857142857.

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2 years ago

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What is 2√20 - 4√45 + 7√12 in simplest radical form? show steps pls

miss Akunina [59]

Exact Form:
8√5+14√3

Decimal Form:
6.36016748

8 0

3 years ago

Which go with which

katrin2010 [14]

Answer:

There are 88 adults and 132 children

Step-by-step explanation:

5 0

3 years ago

Solve: -18 = -3x + 6

Stella [2.4K]

Let's start by moving all like terms to their own sides:

-18 = -3x + 6

3x = 6 + 18

3x = 24

x = 8

8 0

3 years ago

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At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago