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natka813 [3]
3 years ago
10

INEED THIS GRADUATE PLEASE HELP

Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0
Hi, What grade is this?

I am currently doing flvs too and could help you out.
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How many solutions exist for the following system of equations: 4x + y = 7 and 3x - y = 0 a. no solution b. one solution c. infi
Zanzabum
4x+y=7 \\
\underline{3x-y=0} \\
4x+3x=7+0 \\
7x=7 \ \ \ |\div 7 \\
x=1 \\ \\
3x-y=0 \\
3 \times 1-y=0 \\
3-y=0 \ \ \ |+y \\
y=3 \\ \\
(x,y)=(1,3)

The answer is B. one solution.
6 0
3 years ago
Given circle Q with a measure of SR=120° and a radius of 9 feet, as shown below.
Pie

Answer:

18.85 feet

Step-by-step explanation:

Determine the arc length of SR

Arc length = θ/360 × 2πr

r = 9 feet

θ =120°

Arc length = 120/360 × 2 × π × 9

= 18.849555922 feet

Approximately = 18.85 feet

Therefore, the arc length of SR = 18.85 feet

6 0
3 years ago
A band sells tickets to a concert cost either $15 for adults or $10 for students. A total of 150 tickets are sold. If the band m
kodGreya [7K]

Answer:

Number of adult tickets sold= 100

Step-by-step explanation:

Giving the following information:

Adults tickets= $15

Student tickets= $10

Number of tickets sold= 150

Total sales= $2,000

<u>First, we determine the systems of equations:</u>

15*x + 10*y= 2,000

x + y = 150

x= number of adults tickets sold

y= number of students tickets sold

<u>Now, we isolate x in one equation, and substitute it in the other one:</u>

x= 150 - y

15*(150 - y) + 10y = 2,000

2,250 - 15y + 10y = 2,000

250 = 5y

50= y

x= 150 - 50

x= 100

<u>Prove: </u>

15*100 + 10*50= 2,000

100 + 50 = 150

3 0
3 years ago
Read 2 more answers
Jim is investing in the stock market. Jim is hoping to earn $2,000 in interest in order to take a trip to Mexico. Stock A earns
Vanyuwa [196]

Given:

Total amount for investment = $32000

Rate of interest for Stock A = 4%

Rate of interest for Stock B = 7%

Jim is hoping to earn $2,000 in interest.

To find:

The amount of investments in Stock A and Stock B.

Step-by-step explanation:

Let amount of investments in Stock A = $x

Amount of investments in Stock B = $y

Total amount for investment = $32000

x+y=32000        ...(i)

Rate of interests in Stock A and Stock B are 4% and 7%. Total interests is $2000.

0.04x+0.07y=2000           ...(ii)

From (i) and (ii), we get

0.04x+0.07(32000-x)=2000

0.04x+2240-0.07x=2000

-0.03x=2000-2240

-0.03x=-240

Divide both sides by -0.03.

x=\dfrac{-240}{-0.03}

x=8000

Put x=8000 in (i).

8000+y=32000  

y=32000-8000  

y=24000  

Therefore, the amount of investments in Stock A and Stock B are $8000 and $24000 respectively.

8 0
2 years ago
Math question need help with substation please?
Juliette [100K]

<em>2 solutions</em>

<em>X= 16</em>

<em>X=49</em>

Step-by-step explanation:

<em>original equation</em>

<em>x-11√x+28 = 0</em>

<em>   Isolate</em>

<em>     -11√x = -x-28+0</em>

<em>  Tidy up</em>

<em>     11√x = x+28</em>

<em>  Raise both sides to the second power</em>

<em>     (11√x)2 = (x+28)2</em>

<em>After squaring</em>

<em>     121x = x2+56x+784</em>

<em> Plug in 49 for  x </em>

<em>      11√(49) = (49)+28</em>

<em>Simplify</em>

<em>      11√49 = 77</em>

<em>      Solution checks !!</em>

<em>     Solution is:</em>

     x = 49

<em>Plug in 16 for  x </em>

<em>      11√(16) = (16)+28</em>

<em>Simplify</em>

<em>      11√16 = 44</em>

<em>      Solution checks !!</em>

<em>     Solution is:</em>

     x = 16

3 0
3 years ago
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