To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
Answer:
3 years 8 month
Step-by-step explanation:
Given 7 years 6 months - 3 years 10 months
Step 1: Firstly we should subtract months from months then after from year to year.
Step 2: 6 months is less than 10 months so we have to borrow 1 year and add it to the months.
Step 3: Adding 1 year to 6 months we get 18 months.
Step 4: Now we have to subtract 3 years 10 months from 6 years 18 months.
Step 5: After subtracting we get 3 years 8 months.
Thus the answer is 3 years 8 months.
Answer:
A
Step-by-step explanation:
Answer:
276 4/7 ft
Step-by-step explanation:
Let r1 represent the radius of the inner circle. Then its circumference in feet is ...
C = 2πr
66 = 2π(r1)
If the radius of the outer circle is (r1 +44), then its circumference is ...
C = 2π(r1 +44) = 2π(r1) +2π(44)
C = 66 +88π
Then the difference in the circumferences is ...
(66 +88π) - (66) = 88π
Using the given value of π, the difference in circumferences is ...
(88 ft)(22/7) = 1936/7 ft = 276 4/7 ft
Answer:
I would assume it's all but the second one (earned $60 over the summer=false)
