Solve for a. 4a+5=2+3.25a4a+5=2+3.25a
2 answers:
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Answer:
A.-
D.
E.
Step-by-step explanation:
Like terms must have the same variable, in this case x, and the same exponent, in this case 2. Since the original term is , the like terms will be those that contain
, regardless of whether their coefficient or sign is different.
Analyzing the options:
A.-
We have the same variable and the same exponent , so it is a like term.
B.
You have the same variable x but not the same exponent. So it's not a like term of
C.
Same variable but as in the previous case, the exponent is different, it is a 3 and it should be a 2, so it is not a similar or like term.
D.
In this option we do have the , so it is a like term of
E.
It is also a like term because it contains the .
In summary the like terms are:
A.-
D.
E.
Answer:
Step-by-step explanation:
The given equation is :
Where
s is displacement
u is the initial velocity
a is acceleration
t is time
If u = 0, the above equation become,
Hence, the value of t is equal to .