-8Q+6+30-1 Help plz and please explain how

Mathematics

2 answers:

nadya68 [22]3 years ago

8 0

This is just an expression. It's not an equation, so there's nothing to solve for.

The only thing you can do here is add like terms:

$-8Q+6+30-1 = -8Q+(6+30-1)=-8Q+35$

Viefleur [7K]3 years ago

4 0

Answer:

-8Q+6+30-1

-8Q+36-1

-8Q+35

Step-by-step explanation:

-8Q cannot combine with 6, 30, or -1

when someone says "combine like terms," they mean that if a number has a letter with it and another number does not have a letter or has a different letter, then the first term cannot combine with the second

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There are two conditions that need to be in place.

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Step-by-step explanation:

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3 years ago

Can someone know this 13 and 14 and tell me if 12 is right?

skad [1K]

12)

well, the picture has a length of (x + 2.5) and a width of (x).

if we extend the picture 1 inch on all sides, it'll end up like the picture below.

$\bf (1+x+2.5+1)(1+x+1)\implies (x+4.5)(x+2)\implies \stackrel{\mathbb{FOIL}}{x^2+6.5x+9}$

13)

let's find the area of the larger rectangle, that includes the smaller rectangle, and then let's find the area of the smaller rectangle, and after <u>subtracting the smaller area from the larger area</u>, what's leftover is the shaded region.

$\bf \stackrel{\textit{larger area}}{(9x)(6x)}-\stackrel{\textit{smaller area}}{(3x-2)(4x)}\implies 54x^2-(12x^2-8x) \\\\\\ 54x^2-12x^2+8x\implies 42x^2+8x$

14)

we'll do the same thing here as we did in 13)

$\bf \stackrel{\textit{larger area}}{(4x+3)(2x+2)}-\stackrel{\textit{smaller area}}{(x+5)(x+1)}\implies \stackrel{FOIL}{8x^2+14x+6}~~-~~\stackrel{FOIL}{(x^2+6x+5)} \\\\\\ 8x^2+14x+6~~~~-~~x^2-6x-5\implies 7x^2+8x+1$