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2 years ago

Please I really need the answer for this

Mathematics

1 answer:

Minchanka [31]2 years ago

7 0

Answer:

The third option

Step-by-step explanation:

GPE = mgh

Since the baseball has a larger mass as compared to the ping pong ball and is 50 feet off the ground which means that it has the highest height, the GPE will be the greatest

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I need help would really appreciate it ASAP

Darina [25.2K]

Answer:

angle c should be 65 as for the sides i don't know sorry

Step-by-step explanation:

8 0

3 years ago

Leah loves chicken wings and is comparing the deals at three different restaurants. Buffalo Bills has 88 wings for \$7$7. Buffal

Ksivusya [100]

Answer:

Buffalo mild wings offers the lowest price per wing ($0.83).

Step-by-step explanation:

Let us find unit price per buffalo wing of each restaurant.

$\text{Unit rate for buffalo bills}=\frac{\$7}{8\text{ wings}}$

$\text{Unit rate for buffalo bills}=\frac{\$0.875}{\text{ wing}}$

Upon rounding our answer to nearest cent we will get,

$\text{Unit rate for buffalo bills}=\frac{\$0.88}{\text{ wing}}$

Therefore, buffalo bills offers each wing for $0.88.

$\text{Unit rate for buffalo mild wings}=\frac{\$10}{12\text{ wings}}$

$\text{Unit rate for buffalo mild wings}=\frac{\$0.83333}{\text{ wing}}$

Upon rounding our answer to nearest cent we will get,

$\text{Unit rate for buffalo mild wings}=\frac{\$0.83}{\text{ wing}}$

Therefore, buffalo mild wings offers each wing for $0.83.

$\text{Unit rate for wingers}=\frac{\$17}{20\text{ wings}}$

$\text{Unit rate for wingers}=\frac{\$0.85}{\text{ wing}}$

Therefore, wingers offers each wing for $0.85.

We can see that buffalo mild wings offers the lowest price per wing that is $0.83 per wing.

3 0

3 years ago

Please help this is hard math

Rainbow [258]

Answer:

$y=-4x+2$

Step-by-step explanation:

First we find the slope of the line AB passing through the point (2,0)
line AB is perpendicular to the line $y=\frac{1}{4}x-3$ , this equation is slope intercept for, which is $y=mx+b$ so our m or slope is $\frac{1}{4}$
Since the slope of line AB is perpendicular to $m=\frac{1}{4}$ then we use the equation $slope of line1\times slopeofline2=-1$ , so what do we multiply $\frac{1}{4}$ by to get -1? -4 right, so that's the slope of line AB with the point (2,0)
Now line CD is parallel to line AB, that means it has the same slope as AB, so slope of CD is -4
So we make the equation $y-y_1=m(x-x_1)$ so m= -4 and our point is (-1,6)
$y-(6)=-4(x-(-1)\\y-6=-4x-4\\y=-4x-4+6\\y=-4x+2$ thats the equation of line side CD

6 0

2 years ago

Read 2 more answers

Which ordered pair is a solution of the equation −1/4x + 6 = y?

il63 [147K]

Answer:

Step-by-step explanation:

6 0

2 years ago

Suppose the number of insect fragments in a chocolate bar follows a Poisson process with the expected number of fragments in a 2

leonid [27]

Answer:

a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b)0.6004

c)19.607

Step-by-step explanation:

Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2

X ~ Poisson(A) where $\lambda = \frac{10.2}{200} = 0.051$

a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

$\frac{1}{4} \times 200 = 50$

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55

So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment

Let X denotes the number of grams to be eaten before another fragment is detected.

$P(X>10)= e^{-\lambda \times x}= e^{-0.051 \times 10}= e^{-0.51}=0.6004$

c)The expected number of grams to be eaten before encountering the first fragments :

$E(X)=\frac{1}{\lambda}=\frac{1}{0.051}=19.607 gram$ s

7 0

3 years ago