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2 years ago

A loan was taken out for $1000 Sierra pays $50 per month what is the equation ?

Mathematics

2 answers:

Marina CMI [18]2 years ago

5 0

Answer:

1000-50m

Step-by-step explanation:

kipiarov [429]2 years ago

4 0

Well judging off how this is worded if she's paying back the loan then it would be 1000 divided by 50=x the answer without interest if it was towards something else I need to know the the amount .

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Xelga [282]

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3 years ago

kherson [118]

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8 0

3 years ago

the number of men is five eights of the number of women working in a factory if there is 24 more women than men how many workers

Anna [14]

Answer:

104

Step-by-step explanation:

women = 8/8

men = 5/8

all workers = 8/8 + 5/8 = 13/8

extra women workers = 8/8 - 5/8 = 3/8

so...

3/8 = 24

13/8 = x

( cross multiplication method)

3/8 x = 39

x = 104

Hence, there are 104 workers

6 0

1 year ago

Read 2 more answers

Given the two points (0,4) and (2, 6), what would the numerator of the equation for slope be?

serious [3.7K]

6-4 because the equation for slope is m=y2-y1/x2-x1

6 0

2 years ago

Read 2 more answers

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

3 years ago