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ryzh [129]
3 years ago
12

Y''+2y'+y=2e^(-t) find the general solution of the giving nonhomogenous differential equation

Mathematics
1 answer:
Degger [83]3 years ago
3 0
<span>The general solution of the differential equation y</span><span>'' + 2y' + y = 2e^(-t) is (c1 + c2 x) e^-x</span>
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Using the graph below, find r(-3) please
ruslelena [56]

Considering the given graph, it is found that the numeric value of the function r(x) at x = -3 is of 2.

<h3>How to find the numeric value of a function given it's graph?</h3>

The numeric value of a function is the value of y for the given value of x, hence, we have to look at the value of x on the horizontal axis, and verify the equivalent value of y on the vertical axis.

In this problem, when the horizontal axis is of x = -3, the vertical axis is of y = 2, hence the numeric value of the function r(x) at x = -3 is of 2.

More can be learned about the numeric value of a function at brainly.com/question/14556096

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7 0
1 year ago
Plz help I need help plz
Nutka1998 [239]

Answer:

associative! property! of! addition!

Step-by-step explanation:

we change the order of the addends but the sum doesn't change

8 0
2 years ago
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In ΔPQR, p = 95 inches, q = 64 inches and ∠R=53°. Find the area of ΔPQR, to the nearest square inch.
Elena L [17]
AREA = 2428

c= 76
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4 0
2 years ago
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Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0
3 years ago
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Find the slope of the line <br> y= 9/2x<br> .
Sedbober [7]
Y = 9/2x is in slope intercept form (y = mx+b) where m represents the slope and b represents the y-intercept.

In this case, 9/2 is the slope.
7 0
3 years ago
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