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3 years ago

The area of a triangle is 6,384cm ^ 2. Its base measures 93cm; How much is it's height?

Mathematics

1 answer:

Citrus2011 [14]3 years ago

6 0

the height is 137.29

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3 years ago

Find the value of x. Area of circle = 25(pi) radius = x + 3

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3 years ago

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Jane made a mistake when writing down a mutliplication , and she multiplied by 54 instead of 45. Her answer was 198 more than it

BARSIC [14]

Answer:

Step-by-step explanation:

Given that:

Let number multiplied by 54 = x

Let output = y

x * 54 = y + 198

x * 45 = y

54x = y + 198 - - - (1)

45x = y - - - (2)

Put y = 45x in (1)

54x = 45x + 198

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3 years ago

Solve using the quadratic formula 2x^2+8x-5=0

Ede4ka [16]

Step-by-step explanation:

Hey there!!

Given,

${x}^{2} + 8x - 5 = 0$

Comparing it with ax^2+bx+c =0 we get,

a= 1, b= 8, c= -5.

Using formula,

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

Keep all values,

$x = \frac{ - 8 + - \sqrt{ {8}^{2} - 4 \times 1 \times ( - 5)} }{2 \times 1}$

$x = \frac{ - 8 + - \sqrt{64 + 20} }{2}$

$x = \frac{ - 8 + - \sqrt{84} }{2}$

$x = \frac{ - 8 + - 2 \sqrt{21} }{2}$

Taking negative,

$x = \frac{ - 8 - 2 \sqrt{21} }{2}$

$x = \frac{ - 2(4 + \sqrt{21}) }{2}$

$x = 4 + \sqrt{21}$

Similarly, taking positive,

$x = \frac{ - 8 + 2 \sqrt{21} }{2}$

$x = \frac{ - 2(4 - \sqrt{21} ) }{2}$

$x = 4 - \sqrt{21}$

Therefore, x= (4 + root 21, 4 - root 21).

Hope it helps.....

3 0

3 years ago

The area of ​​a triangle is 6,384cm ^ 2. Its base measures 93cm; How much is it's height?

The area of a triangle is 6,384cm ^ 2. Its base measures 93cm; How much is it's height?