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musickatia [10]
3 years ago
14

PLEASE HELP! Geometry Question

Mathematics
1 answer:
Ivahew [28]3 years ago
4 0

Answer:

hiii

your answer is option d

HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN

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An after school music program has 15 out 50 students practicing. Write 15/50 (15 over 50) as a decimal and as a percent.
ValentinkaMS [17]
15/50 * 2/2 = 30/100
Now you can easily see decimal and percent form

Decimal: 0.30
Percent: 30 percent
7 0
3 years ago
Read 2 more answers
Part A: how many solutions dose the pair of equations for lines A and B have?
Ede4ka [16]

Any line can be expressed in the form y=mx+b where m is the slope and b is y intercept.

Two lines can either be parallel ,overlap or meet at one point .Let us look at different cases :

1)When two lines are parallel they do not intersect at any point and hence the system of equations have no solution.

2) When two lines overlap each other then the two lines touch each other at infinite number of points and we say the system of equations have infinite solutions.

3) When two lines intersect each other at one point we say the system of equation has one solution.

Part A:

The given lines are intersecting at one point so we have one solution.

Part B:

The point of intersection is the solution to the system of equations .In the graph the point of intersection of the lines is (4,4)

Solution is (4,4)

8 0
3 years ago
Read 2 more answers
there are 6 pure spectral color : red,orange,yellow, green,blue, and violet. some animals cannot see orange or red. what fractio
Gnoma [55]
<span>Bees see “primary colors” as blue, green and ultra violet. <span>They can distinguish yellow, orange, blue-green, violet, purple, as combinations of their three primary colors.</span></span>
8 0
3 years ago
What can you say about the sum of consecutive odd numbers starting with 1? that is, evaluate 1, 1c3, 1c3c5, 1c3c5c7, and so on,
Mice21 [21]

Let us add consecutive odd numbers and try to find any relationship.

1. 1

2. 1+3 = 4 ( square of 2 i.e 2^{2} )

3. 1+3+5 = 9 ( 3^{2} )

4.  1+3+5+7 =  16 (4^{2} )

5. 1+3+5+7+9 = 25 (5^{2} )

6. 1+3+5+7+9+11 = 36 ( 6^{2} )

7. 1+3+5+7+9+11+13 = 49 (7^{2} )

If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to 7^{2}. The sum of the numbers in the fifth line is equal to 5^{2}.

4 0
3 years ago
Find the perimeter.
Burka [1]

Answer:

5 11/13 km

Step-by-step explanation:

4 ( 1 6/13)

4× 19/13

= 5 11/13

6 0
3 years ago
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