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2 years ago

Help please, i have been stuck on this question for 20 minutes AND I DONT GET IT. Please help me.

Mathematics

1 answer:

Ratling [72]2 years ago

5 0

Answer:

Step-by-step explanation:

sorry if im wrong

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The volume of a rectangular prism is 270 cubic centimeters the height of the prism is 5 centimeters. What could the length and w

kotegsom [21]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Volume = 270 cm³

height = 5 cm

length = ?

width = ?

Formula

Volume of a rectangular prism = height x length x width

- Solve for Area of the base (height x length)

Area of the base = Volume / height

-Substitution

Area of the base = 270 / 5

-Result

Area of the base = 54 m²

2.- Find the prime factors of 54

54 2

27 3

9 3

3 3

3.- The possible values of the sidas of the rectangle are:

Combining the prime factor of 54.

Length Width

2 x 3 = 6 and 3 x 3 = 9

or 2 x 3 x 3 = 18 and 3 x 1 = 3

or 3 x 3 x 3 = 27 and 2 x 1 = 2

6 0

3 years ago

For what values of x does 25 Superscript x Baseline = 5 Superscript x squared minus 3?

umka2103 [35]

For this case we have the following equation:

$25^{x} = 5^{ x^2-3}$

Rewriting we have:

$5^{2 (x)} = 5^{ x^ 2-3}\\5^{ 2x} = 5^{ x^ 2-3}$

For expressions to be equal, exponents must be equal. So:

$2x = x ^ 2-3\\x ^ 2-2x-3 = 0$

To factor, we look for two numbers that, when multiplied, result in -3 and when added, result in -2. These numbers are -3 and 1.

$(x-3) (x + 1) = 0$

Thus, the roots are:

$x_ {1} = 3\\x_ {2} = - 1$

Answer:

$x_ {1} = 3\\x_ {2} = - 1$

8 0

3 years ago

Find the area of the circle whose equation is x2+y2=6x-8y

Semenov [28]

Answer:

Given that the equation of a circle is :

$\green{ \boxed{\boxed{\begin{array}{cc} {x}^{2} + {y}^{2} = 6x - 8y \\ = > {x}^{2} + {y}^{2} - 6x + 8y = 0 \\ = > {x}^{2} + {y}^{2} + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\ \\ \sf \: standard \: equation \: o f \: circle \: is : \\ {x}^{2} + {x}^{2} + 2gx + 2fy + c = 0 \\ \\ \sf \: by \: comparing \\ \\ g = - 3 \\ f = 4 \\ c = 0 \\ \\ \sf \: radius \: \: r = \sqrt{ {g}^{2} + {f}^{2} - c } \\ = \sqrt{ {( - 3)}^{2} + {4}^{2} - 0 } \\ = \sqrt{9 + 16} \\ = \sqrt{25} \\ = 5 \: unit \\ \\ \bf \: area \: = \pi {r}^{2} \\ = \pi \times {5}^{2} \\ =\pink{ 25\pi \: { unit }^{2} }\end{array}}}}$

6 0

3 years ago

3m – 2n = 8, solve for m

leva [86]

Answer:

3m – 2n = 8,

or, 3m = 8+2n

or, m= 8+2n/3

6 0

3 years ago

Read 2 more answers

Given each of the following areas, what would be the radius of each circle? a. A = 530.66 m2 b. A = 907.46 sq. ft. c. A = 379.94

ra1l [238]

Area for a circle is $A= \pi r^2$ . We will fill in each area and then solve for the radius. $530.66m^2= \pi r^2$ and $\frac{530.66m^2}{3.14}=r^2$ . ∴ $169=r^2$ and r = 13. For b, $907.46ft^2= \pi r^2$ and $\frac{907.46ft^2}{3.14}=r^2$ . $289=r^2$ , ∴ r = 17. For c, $379.94mi^2= \pi r^2$ , and $\frac{379.94mi^2}{3.14}=r^2$ . ∴, $121=r^2$ and r = 11. For d, $1962.5cm^2= \pi r^2$ , and $\frac{1962.5cm^2}{3.14}=r^2$ . ∴, $625=r^2$ so r = 25. And there you have it!

3 0

3 years ago