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2 years ago

Help please, i have been stuck on this question for 20 minutes AND I DONT GET IT. Please help me.

Mathematics

1 answer:

Ratling [72]2 years ago

5 0

Answer:

Step-by-step explanation:

sorry if im wrong

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Y-1.6=8.76 what is y

Verizon [17]

Answer:

y = 10.36

Step-by-step explanation:

y - 1.6 = 8.76

add 1.6 to both sides

y - 1.6 + 1.6 = 8.76 + 1.6

y = 10.36

8 0

2 years ago

Read 2 more answers

The wheels on Darlene's car have on 11-inch radius. If the wheels are rotating at a rate of 378 rpm, find the linear speed in mi

elena-s [515]

Answer:

The linear speed in which Darlene is traveling is 24.74 miles per hour.

Step-by-step explanation:

The wheel experiments rolling, which is a combination of translation and rotation. The point where linear speed happens is located at geometrical center of the wheel and instantaneous center of rotation is located at the point of contact between wheel and ground. The linear speed ( $v$ ), measured in inches per second, is defined by following expression:

$v = R\cdot \omega$ (1)

Where:

$R$ - Radius of the wheel, measured in inches.

$\omega$ - Angular speed, measured in radians per second.

If we know that $R = 11\,in$ and $\omega \approx 39.584\,\frac{rad}{s}$ , then the linear speed, measured in miles per hour, in which Darlene is traveling is:

$v = 11\,in\times \frac{1\,mi}{63360\,in} \times 39.584\,\frac{rad}{s}\times \frac{3600\,s}{h}$

$v \approx 24.74\,\frac{mi}{h}$

The linear speed in which Darlene is traveling is 24.74 miles per hour.

8 0

3 years ago

Solve the following equation 5(y+4) =4(y+5)

kvv77 [185]

Answer:

Step-by-step explanation:

5(y+4) = 4(y+5)

5y+20 = 4y + 20

5y = 4y

y=0

6 0

3 years ago

Area of this rectangular pyramid please

dalvyx [7]

The rectangular prism has an area of 1188.

4 0

3 years ago

Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling

arlik [135]

a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

<h3>What is tension?</h3>

This is the opposing force in a stretched material.

<h3>a. Tension in the string</h3>

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

T = tension in sring and
W = weight of particle = mg where
m = mass of particle and
g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

<h3>b. Tension in chain</h3>

The expression for the tension in the chain is T = 2mg

<h3 />

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

T' = tension in chain and
T = tension in each string

So, T' = T + T

T' = 2T

T' = 2W

T' = 2mg

So, the expression for the tension in the chain is T = 2mg

<h3 />

Learn more about tension here:

brainly.com/question/24994188

5 0

2 years ago