Question

Ther are 6 girls and 7 boys in a class. A team of 10 players is to be selected from the class. How many different combinations of players are possible

Answer 1

Answer:

$13C10 =286$

Step-by-step explanation:

To solve this problem we must use the formula of combinations.

$nCr =\frac{n!}{r!(n-r)!}$

Where n is the number of players that there are and elect r of them

In this case there are $7 + 6 = 13$ players and you choose 10 of them

Then we look for  13C10

$13C10 =\frac{13!}{10!(13-10)!}$

$13C10 =\frac{13!}{10!*3!}$

$13C10 =286$

There are 286 possible combinations