How do I solve 3x+17 greater than or equal to (you can’t do the sign on a phone but it would be _>) 5

Mathematics

1 answer:

Kobotan [32]2 years ago

5 0

<h3><u>The value of x is greater than or equal to -4.</u></h3>

(3x + 17) ≥ 5

Subtract 17 from both sides.

3x ≥ -12

Divide both sides by 3.

x ≥ -4

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Water is pumped out of a holding tank at a rate of 6-6e^-0.13t liters/minute, where t is in minutes since the pump is started. I

astraxan [27]

Procedure:

1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and

2) Substract the result from the initial content of the tank (1000 liters).

Hands on:

Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =

= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =

6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters

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2 years ago

A 20 foot ladder leaning against a wall is used to reach a window that is 17 feet above the ground. How far from the wall is the

GarryVolchara [31]

The bottom of the ladder is 10.5 feet away from the wall

Step-by-step explanation:

The given scenario forms a right triangle.

Where

The length of ladder will be the hypotenuse

The wall on which the window is situated will ebt he perpendicular and

The distance between the foot of ladder and the wall will be the base

So,

Hypotenuse = H = 20 foot

Perpendicular = P = 17 feet

Base = B = ?

Using the Pythagoras theorem

$H^2=P^2+B^2\\(20)^2=(17)^2+B^2\\400=289+B^2\\400-289=B^2\\B^2=111\\Taking\ square\ root\ on\ both\ sides\\\sqrt{B^2}=\sqrt{111}\\B=10.53\\Rounding\ off\ to\ the\ nearest\ tenth\\B=10.5$