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AnnZ [28]
3 years ago
8

Describe a single transformation the has the same effect as rotations a shape 90 degrees clockwise around the origin, then refle

cting the result over the x-axis
Mathematics
1 answer:
GaryK [48]3 years ago
4 0

Answer:

reflection over the line y = x

Step-by-step explanation:

A transformation is the movement of a point from its initial location to its new location. If a shape is transformed then all its points are also transformed. Types of transformations are rotation, translation, dilation and reflection.

If apoint A(x, y) is rotated 90 degrees clockwise around the origin then the new location is at A'(y, -x). Then if the point A'(y, -x) is reflected over the x axis the new location is A" (y, x)

If a point A(x , y) is reflected over y = x, the new coordinate is A'(y , x)

A transformation that corresponds to rotating a shape 90 degrees clockwise around the origin, then reflecting the result over the x-axis is a reflection over the line y = x

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given the linear equation c=30+6y where c is the cost of the dictionary y years after 1904. determine the cost of the dictionary
Lina20 [59]

Answer:756

Step-by-step explanation:6(121)+30

121 because 2025-1904=121 numbers of years in between

7 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Andrew [12]
Answer:  x = 9.611 ;  or ;  x = 9  11/18 .
_________________________________________________
Explanation:
________________________________________________

All angles of any triangle must add up to 180 degrees.

So,  (10x - 4)  + (8x + 3) + 91 = 180 ;  Solve for "x" ; 
___________________________________________
    10x - 4 + 8x + 3 + 81 = 180 ;

Combine the "like terms" on the left-hand side of the equation:
___________________________________________
      +10x + 8x = 18x ;
        
       - 4 + 3 + 8 = 7 ;
____________________________
          18x  +  7 = 180 ;
___________________________________________
   Subtract  "7" from each side of the equation:
___________________________________________
         18x + 7 - 7 = 180 - 7 ;
___________________________________________
to get:  
  
         18x  = 173 ; 
_________________________________
Divide EACH side of the equation by "18" ; to isolate "x" on one side of the equation;  and to solve for "x" ; 
_________________________________
         18x / 18  = 173 / 18 ;
_________________________________
                   x = 9.6111111111111111....
_____________________________________
  
Write as:  9.611 ;  or;   9  11/18.
____________________________________



7 0
4 years ago
What is the function? F(x)=2x^2-3x+1
olasank [31]

Answer:

To satisfy the hypotheses of the Mean Value Theorem a function must be continuous in the closed interval and differentiable in the open interval.

Step-by-step explanation:

As f(x)=2x3−3x+1 is a polynomial, it is continuous and has continuous derivatives of all orders for all real x, so it certainly satisfies the hypotheses of the theorem.

To find the value of c, calculate the derivative of f(x) and state the equality of the Mean Value Theorem:

dfdx=4x−3

f(b)−f(a)b−a=f'(c)

f(x)x=0=1

f(x)x=2=3

Hence:

3−12=4c−3

and c=1.

4 0
3 years ago
Read 2 more answers
What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?
victus00 [196]
Given the following information:

\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] 
\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]
\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\
\end{tabular}
\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\
\end{tabular}

Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\  \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\  \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}



Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

For bust: = 0.21(0.23) + 0.21(0.29) + 0.58(-0.14) = 0.0483 + 0.0609 - 0.0812 = 0.028 or 2.8%

Expected return = 0.66(0.2224) + 0.34(0.028) = 0.1468 + 0.00952 = 0.1563 or 15.63%

The variance is given by

0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\  \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\  \\ =0.00288+0.0056=\bold{0.00848}
4 0
4 years ago
Write the integer that represents the situation.
kotegsom [21]

Answer:

what im thinking is $65

Step-by-step explanation:

3 0
3 years ago
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