We can't write the product because there is no common input in the tables of g(x) and f(x).
<h3>Why you cannot find the product between the two functions?</h3>
If two functions f(x) and g(x) are known, then the product between the functions is straightforward.
g(x)*f(x)
Now, if we only have some coordinate pairs belonging to the function, we only can write the product if we have two coordinate pairs with the same input.
For example, if we know that (a, b) belongs to f(x) and (a, c) belongs to g(x), then we can get the product evaluated in a as:
(g*f)(a) = f(a)*g(a) = b*c
Particularly, in this case, we can see that there is no common input in the two tables, then we can't write the product of the two functions.
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A relation is a function if it has only One y-value for each x-value. Functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6
<h3>What is a function?</h3>
A relation is a function if it has only One y-value for each x-value.
The given function is
f(x)=2x²-4x+2
Put x=2/3
f(2/3)=2(2/3)²-4(2/3)+2
=2(4/9)-8/3+2
=8/9-8/3+2
=(8-24+18)/9
f(2/3)=2/9
Now f(x)=4x²+2x-6
Put x=1/4
f(1/4)=4(1/4)²+2(1/4)-6
=4/16+2/4-6
=1/4+1/2-6
= 1+2-24/4
f(1/4)==-21/4
Hence functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6
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Answer:
yo no habla english nomas espanol
Step-by-step explanation:
B. it’s the change in y over the change in x
Answer:
x=70
y= 40
Step-by-step explanation:
the triangle containing x is an isosceles triangle so two of the sides are 55.
55+55+x=180.
110+x=180
110-110+x=180-110
x=70
Triangle BAC is equilateral so 180/3=60. Now
x+60+c=180
70+60+c=180
130+c=180
130-130+c=180-130
c=50
That gives us one corner of triangle CBD. We know a second angle is 90 so
50+90+y=180
140+y=180
140-140+y=180-140
y=40
I think that is correct but you are free to check it yourself