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makkiz [27]
3 years ago
11

Someone, please help me

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0

Answer:

≈ $937

Step-by-step explanation:

to answer this, we have to use the compound interest formula which is:

A = P(1 + r/n)^nt

the meanings of each variable are:

A = result

P = principal amount

r = rate (in decimal form)

n = the number of compound periods (eg: annually, quarterly, etc)

t = time

in the word problem, we need to solve for A. we are given P, r, n, and t.

P = 800

r = 0.02 also known as 2%

n = 1 keyword being <em>annually</em> which is equal to the value of 1

t = 8

we can plug these values into the formula:

A = 800(1 + 0.02/1)^(^1^)^(^8^)

we can use a calculator to calculate this easier but ill break it down:

A = 800(1 + 0.02/1)^8

A = 800(1.02)^8

A = 800(1.02)^8

A = 800(1.17165938)

A ≈ 937.327

we can round 937.327 to the nearest dollar which is $937

Carl would have earned $937 over the course of 8 years

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PLEASE HELP QUICK
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1) The probability of getting a queen is 187/10000 which is 0.0187 = 1.87%


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You may need to round the answers. It doesn't say if they need to be rounded or not.

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Step-by-step explanation:

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Please I need help with this!!!!!!!
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Answer:

Step-by-step explanation:

1). Step 4:

   x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}

   x=\sqrt[3]{5^4} [Since, a^{\frac{1}{3}}=\sqrt[3]{a}]

   x=\sqrt[3]{5\times 5\times 5\times 5}

   Step 5:

   x=\sqrt[3]{(5)^3\times 5}

   x=\sqrt[3]{5^3}\times \sqrt[3]{5}

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

   (3x-1)^{\frac{1}{5}}=2

   Step 1:

   (3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}

   Step 2:

   (3x-1)=2^5

   Step 3:

   3x=32+1

   Step 4:

   x=11

4). By substituting x=11 in the original equation.

   (3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}

                         =(2^5)^\frac{1}{5}

                         =2

There is no extraneous solution.

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2 years ago
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