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iVinArrow [24]
3 years ago
12

In a set of five consecutive integers, the smallest integer is more than $\frac23$ the largest. What is the smallest possible va

lue of the sum of the five integers?
Mathematics
2 answers:
Goryan [66]3 years ago
4 0

Answer:

 55

Step-by-step explanation:

Let x represent the middle integer. Then the smallest is x-2 and the largest is x+2. Your requirement is that ...

  (x-2)/(x+2) > 2/3

  3x -6 > 2x +4 . . . . cross multiply

  x > 10 . . . . . . . . . . .add 6-2x

The smallest integer satisfying this requirement is x=11. The sum of the 5 integers is 5x = 55.

The smallest sum is 55.

miv72 [106K]3 years ago
4 0

Answer:

55

Step-by-step explanation:

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(12/-3)+(-14*4)
(-4)+(-56)
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WHICH EXPRESSION REPRESENTS THE SUM OF (2X-5Y) and (x+y)?
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Step-by-step explanation:

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Mandy used the graph to write the equation of the line it represents. She took these steps. 1. y−intercept = (0, 2) 2. Slope = r
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Based on the information given about the equation, y will be 0.5x + 2.

<h3>How to illustrate the equation?</h3>

From the information given, it should be noted that the equation of the line it represents was given and the y intercept is = (0, 2).

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