In a set of five consecutive integers, the smallest integer is more than $\frac23$ the largest. What is the smallest possible va lue of the sum of the five integers?
2 answers:
Answer:
55
Step-by-step explanation:
Let x represent the middle integer. Then the smallest is x-2 and the largest is x+2. Your requirement is that ...
(x-2)/(x+2) > 2/3
3x -6 > 2x +4 . . . . cross multiply
x > 10 . . . . . . . . . . .add 6-2x
The smallest integer satisfying this requirement is x=11. The sum of the 5 integers is 5x = 55 .
The smallest sum is 55 .
Answer:
55
Step-by-step explanation:
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