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iVinArrow [24]
3 years ago
12

In a set of five consecutive integers, the smallest integer is more than $\frac23$ the largest. What is the smallest possible va

lue of the sum of the five integers?
Mathematics
2 answers:
Goryan [66]3 years ago
4 0

Answer:

 55

Step-by-step explanation:

Let x represent the middle integer. Then the smallest is x-2 and the largest is x+2. Your requirement is that ...

  (x-2)/(x+2) > 2/3

  3x -6 > 2x +4 . . . . cross multiply

  x > 10 . . . . . . . . . . .add 6-2x

The smallest integer satisfying this requirement is x=11. The sum of the 5 integers is 5x = 55.

The smallest sum is 55.

miv72 [106K]3 years ago
4 0

Answer:

55

Step-by-step explanation:

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Cereal B

Step-by-step explanation:

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As such we cannot compare unless we make it unit rate for same number of units

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What is 2.58333333333 as a fraction?
liberstina [14]

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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Which unit of measure would be appropriate for the volume of a cube with sides of 2 meters
Brrunno [24]

Answer:

The unit of measure appropriate is cubic metre or cubic meter (m³)

Step-by-step explanation:

we know that

The volume of a cube is equal to

V=b^3

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In this problem we have

b=2\ m

substitute in the formula of volume

V=2^3

V=8\ m^3

therefore

The unit of measure appropriate is cubic metre (m³)

4 0
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