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iVinArrow [24]
3 years ago
12

In a set of five consecutive integers, the smallest integer is more than $\frac23$ the largest. What is the smallest possible va

lue of the sum of the five integers?
Mathematics
2 answers:
Goryan [66]3 years ago
4 0

Answer:

 55

Step-by-step explanation:

Let x represent the middle integer. Then the smallest is x-2 and the largest is x+2. Your requirement is that ...

  (x-2)/(x+2) > 2/3

  3x -6 > 2x +4 . . . . cross multiply

  x > 10 . . . . . . . . . . .add 6-2x

The smallest integer satisfying this requirement is x=11. The sum of the 5 integers is 5x = 55.

The smallest sum is 55.

miv72 [106K]3 years ago
4 0

Answer:

55

Step-by-step explanation:

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