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aleksley [76]
3 years ago
10

What interval consists of all $u$ such that neither $2u$ nor $-20u$ is in the interval $(-\infty,-1)$ ?

Mathematics
1 answer:
nadezda [96]3 years ago
7 0

Answer:

[-1/2,1/20]

Step-by-step explanation:

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The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of
lora16 [44]

Answer:

The dimension of the sandbox is (2x+1) by (x - 3)

Step-by-step explanation:

It seems the complete question will be:

The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of x.

Step-by-step explanation:

From the question, the given expression is 2X^2-5x-3. This can be rewritten as

2x^{2} -5x-3

If the area of the sandbox in park is represented by this expression, then the dimensions of the sandbox will be the product of the factors. To determine the factors, we will factorize the given quadratic expression.

Factorizing the expression 2x^{2} -5x-3, we get

2x^{2} -6x+x-3

2x(x-3)+1(x-3)

(2x+1)(x-3)

Hence, the dimension of the sandbox is (2x+1) by (x - 3)

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What is the linear equation in standard form: 3x = -5y + 7
Licemer1 [7]

Answer:

<em><u>3x + 5y = 7</u></em>

Step-by-step explanation:

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In a recent
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Answer:collecting data

Step-by-step explanation:

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What is 3/7 as decimal
maksim [4K]

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0.428571429

Step-by-step explanation:

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Use long or synthetic division to find the following quotients <br>(x^3+2x^2!22x-45)÷(x+5) ​
svetoff [14.1K]

Answer:

\boxed{\textsf{ The quotient is $\sf x^2-3x-7$ and the remainder is (-10).}}

Step-by-step explanation:

Here we will be using long division method to find the quotient . Here we need to divide (x³+2x²-22x-45) and (x+5) . So lets divide .

x+5) x³+2x²-22x-45 ( x² -3x -7

x³ + 5x²

- -

______________

- 3x²-22x -45

-3x² -15x

+ +

______________

-7x -45

-7x -35

______________

-10

<u>Quotient</u><u> </u>= x² -3x -7

<u>Remainder </u>= (-10)

<h3><u>★</u><u>Hence </u><u>the</u><u> </u><u>quotient</u><u> </u><u>is </u><u>x²</u><u> </u><u>-3x </u><u>-</u><u>7</u><u> </u><u>and </u><u>the</u><u> </u><u>remainder</u><u> </u><u>is </u><u>(</u><u>-</u><u>1</u><u>0</u><u>)</u><u> </u><u>.</u></h3>
7 0
3 years ago
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