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Arisa [49]
3 years ago
15

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Mathematics
1 answer:
Hatshy [7]3 years ago
3 0

Answer:

The change in the area of the rectangle is 0 square feet

Step-by-step explanation:

To solve this problem we have to calculate the area of ​​the two rectangles that give us

first we have to know the formula to calculate the area of ​​a rectangle

a = area

l = length  = 12ft

w = width = 5ft

a = l * w

we replace the known walues

a = 12ft * 5ft

a = 60ft²

we do the same with the other rectangle, but first we have to calculate its sides

w = 5ft - (5ft * 20/100)

w = 5ft - 1ft

w = 4ft

l = 12ft + (12ft * 25/100)

l = 12ft + 3ft

l = 15ft

a2 = 15ft * 4ft

a2 = 60ft²

to calculate the change in the area we subtract (a - a2)

a - a2 =

60ft² - 60ft² = 0ft²

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Find the equations for the lines through the point (a,
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The slope of the perpendicular line  is -1/m.

it passes through the point (a,c) therefore:-

y - c = -1/m(x - a)

y  = -1/m x + a/m + c  answer


Parallel line:-

c = m(a) + b
b = c - ma

y = mx + c - ma    Answer
4 0
3 years ago
Please help i have an F right now
AnnZ [28]

Answer:

4

Step-by-step explanation:

If you add up all of those, you get 24. Then you divide by 6. 24/6 = 4.

7 0
3 years ago
What is the answer to 3x-17=7x-9​
GrogVix [38]

Answer:

x=-2

Step-by-step explanation:

  -4x - 8  =   -4 • (x + 2)

5 0
3 years ago
Read 2 more answers
4.
marta [7]

Answer:

a) (x-2)(x-6) + (y-5)(y-11) =0\Rightarrow (x-4)^{2}+(y+3)^{2}=68\\C(4,-3) \:r=\sqrt{68} b) (a,b) (c, d) As long as (a,b) and (c,d) are the endpoints of of the diameter.

Step-by-step explanation:

a)

1) The reduced formula of the Circumference is given by:

(x-a)^{2}}+(y-b)^{2}=r^{2}

2) Let's expand the factored one into one closer to the pattern above:

x^{2}-8x+12+y^{2}+6y-55=0\Rightarrow x^{2}-8x+y^{2}+6y=43

3) Completing the square for both trinomials:

(x-4)^{2}+(y+3)^{2}=43+16+9\Rightarrow (x-4)^{2}+(y+3)^{2}=68

4) In the Reduced Formula, (x-a)^{2}}+(y-b)^{2}=r^{2},

C(a,b) \Rightarrow C(4,-3) \:the\:radius\:is\:r=\sqrt{68} \Rightarrow r=2\sqrt{17}

b) Using the previous example to show this:

When we  factor this way

(x-a)(x -c) + (y -b)(y-d) = 0

We are indeed, naming "a" and "b", the coordinates of (a, b) of the first endpoint and "b" and "d" the second endpoint as well.Id est, D (2, 5) and B (6,-11).

The radius, is \sqrt{68} \cong 8.25

So yes, the equation of the circle can be written as

(x-a)(x -c) + (y -b)(y-d) = 0

As long as (a,b) and (c,d) are the endpoints of of the diameter.

d_{AC}=d_{BC}=R

3 0
3 years ago
What are the values of rand s?<br><br>​
Vitek1552 [10]

Answer:

s=15

r=10

Step-by-step explanation:

What we know)

The measure of a line is 180º

If two parrel lines are cut by a transversal, the corresponding angles are congruent (corresponding angles postulate)

What we can figure out)

The angle measuring 3r+3s and 6r+3s are on the same line, so

3r+3s+6r+3s=180

3r+3s and 6r+s are corresponding, so

3r+3s=6r+s

Solve)

Now, we just need to solve the equations.

3r+3s+6r+3s=180 can be condensed into 9r+6s=180 by combining like terms. Then, you can divide by 3 to get 3r+2s=60

3r+3s=6r+s can be turned into 2s=3r by subtracting 3r and s.

So we have 3r+2s=60 and 2s=3r

We can substitute 2s for 3r

2s+2s=60

4s=60

s=15

Then, we can plug s=15 into the equation

2(15)=3r

30=3r

r=10

7 0
2 years ago
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