If you need the geometry and trigonometry I'll post those. Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span>
<span>
<span>
66.78</span> </span>f</span>eet
Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.
I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.
Answer:
55°
Step-by-step explanation:
d = 180 - 80 = 100
100 + 130 + 90 + (180 - 85) + (180 - c)
= 540
595 - c = 540
c = 595 - 540
c = 55°
Negative x positive = negative
Negative x negative = positive
-4 x 8 = -32
-4 x -1 = 4
-4 x -5 = 20
-4 x 9 = -36
Answer: |-32 4 20 -36|
Answer:
123414
Step-by-step explanation:
12
213
213
32
Answer:
7/12 please give brainliest.
Step-by-step explanation:
