Answer:
The distance bicycle tire travels is <u>1946.8 cm</u>.
Step-by-step explanation:
Given:
Diameter of bicycle tire = 62 cm.
The bicycle tire travels in 10 revolutions.
Now, to find the distance the bicycle tire travels in 10 revolutions.
Diameter = 62 cm.
Radius (r) =
So, we get the circumference first by putting formula:
Thus, we get the <u><em>circumference of tire 194.68 cm.</em></u>
<u><em>Number of revolutions the tire travels = 10.</em></u>
Now, to get the distance the bicycle tire travels we multiply circumference of tire by number of revolutions the tire travels:
Therefore, the distance bicycle tire travels is 1946.8 cm.
Answer:
Step-by-step explanation:
C
Answer:
<em>Thus, the dimensions of the metal plate are 10 dm and 8 dm.</em>
Step-by-step explanation:
For a quadratic equation:
The sum of the roots is -b and the product is c. Note the leading coefficient is 1.
We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:
P=2(L+W)=36
A=L.W=80
Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.
Thus we use the semi perimeter instead as P/2=L+W=18
The quadratic equation is, then:
Factoring by finding two numbers that add up to 18 and have a product of 80:
The solutions to the equation are:
x=10, x=8
Thus, the dimensions of the metal plate are 10 dm and 8 dm.
The system of the equation doesn't give the solution at (-3, -6).
<h2>Given to us</h2>
<h3>Equation 1,</h3>
-4x+y = 6
solve for y
<h3>Equation 2,</h3>
5x-y =21
substitute the value of y in equation 2,
Substitute the value of x in equation 2,
We can see that the solution of the two equations is at (27, 114). Also, it can be verified by plotting the line on the graph.
Hence, the system of the equation doesn't give the solution at (-3, -6).
Learn more about system of equations:
brainly.com/question/12895249
Answer:
Step-by-step explanation:
Build a Polynomial Knowing its Roots
If we know a polynomial has roots x1, x2, ..., xn, then it can be expressed as:
Where a is the leading coefficient.
Note the roots appear with their signs changed in the polynomial.
If the polynomial has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1, then: