Find the area of an isosceles triangle with perimeter of 40 feet and a base of 12 feet. Round to the nearest whole number.
1 answer:
Answer: 76 ft2
Step-by-step explanation:
Perimeter = 2 side length +base length
40 = 2s +12
Solving for s:
40-12 =2s
28 =2s
28/2=s
14ft =side
Since the line which bisects and isosceles triangles is at a right angle to the base we can use the Pythagorean Theorem to find the height (see attachment)
c^2 = a^2 + b^2
Where c is the hypotenuse of the triangle (in this case 14) and a and b are the other sides. (Base divided by 2 is one side, the other side is the height)
Replacing with the values given:
14^2= 6^2 + x^2
196 = 36 + x^2
196-36 = x^2
160 = x^2
√160 = x
x = 12.64 (height)
Area of an isosceles triangle = 1/2 x base x height
A = 1/2 x 12 x 12.64 = 76 ft2
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Answer:
It's position at time t = 5 is 593.
Step-by-step explanation:
The velocity v(t) is the integral of the acceleration a(t)
The position s(t) is the integral of the velocity v(t)
We have that:
The acceleration is:
Velocity:
K is the initial velocity, that is v(0). Since V(0) = 13, K = 13
Then
Position:
Since s(0) = 3
What is its position at time t=5?
This is s(5).
It's position at time t = 5 is 593.