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4 years ago

State the oxidation number assigned to each bold element in the formula: NH4+1 a 3 b -3 c -1 d 6

1 answer:

8 0

The fomula is NH4 (1+)

There are only two elements N and H.

As per oxidation state rules, the most electronegative element will have a negative oxidation state and the other element will have a positive oxidation state.

N is more electronative than H, so H will have a positive oxidation state and nitrogen will have a negative oxidation state.

You can also use the rule that states the hydrogen mostly has 1+ oxidation state,except when it is bonded to metals.

In conclusion the oxidation state of H in NH4 (1+) is 1+.

Now you must know that the sum of the oxidations states equals the charge of the ion, which in this case is 1+.

That implies that 4* (1+) + x = 1+

=> x = (1+) - 4(+) = 3-

Answer: the oxidation state of N is 3-, that is the option b.

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3 years ago

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garri49 [273]

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3 years ago

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3 years ago

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tekilochka [14]

Answer: See below

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protons: 1 amu each

neutrons: 1 amu each

electrons: 0 amu each

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b. Electrons are assigned a mass of 0. They do have a mass, but it is exceedingly small compared to the protons and neutrons, so they are left out of the calculation of an element's mass.

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2 years ago

What happens to the ph of the reaction mixture as the oxidation reaction proceeds in an oxidation of an aromatic side chain?

andrew11 [14]

Answer:

The pH decreases.

Explanation:

Hello,

In organic chemistry, oxidation accounts for either the increasing of C-O bonds or the increasing in the oxygen atoms into the molecule. Thus, if we consider the oxidation from benzyl alcohol to benzoic acid, there will be a carboxyl functional group instead of a hydroxile one. Now, the presence of the polar -O-H bonds that are ionizable, there will be a $H^{+1}$ releasing causing the pH to decrease (increase acidity).

Regards.

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3 years ago