Answer:
The explanations are given in the section below
Explanation:
First step:
We need to understand the acid-base equilibrium of the reaction. Bear in mind that the conjugate acid-base pairs are species that differ by one proton. Furthermore, one is a Lewis acid (meaning the ability to protons) and the conjugate base (accepts protons)
A simple conjugate base is obtained by removing one proton from an acid as shown below:
HX ⇄ A⁻ + H⁺
The diagrams are as follows:
The above question is incomplete, here is the complete question:
Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:
Answer:
The standard molar enthalpy of formation of NO is 90.25 kJ/mol.
Explanation:
To calculate the standard molar enthalpy of formation
...[3]
Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
[1] - [2] = [3]
According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :
=