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2 years ago

Help me pls omg , im stuck

Chemistry

1 answer:

eimsori [14]2 years ago

8 0

Answer:

Explanation:

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A sample of solid NH 4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (at

UNO [17]

Answer:

The answer to the question is

The equilibrium partial pressure (atm) of ammonia, assuming that some solid NH₄HS remains 0.26 atm.

Explanation:

To solve the question, we write out the chemical equation as follows

NH₄HS (s) ⇄ NH₃ (g) + H₂S (g)

From the above equation, it is observed that only the gaseous products contribute to the partial pressure

Kp =PNH₃·PH₂S where at Kp = 0.070 and PNH₃, PH₂S are the partial pressures of the gases

However since the number of moles of both gases are equal, therefore by Avogadro's law PNH₃ = PH₂S

Then PNH₃ = √(0.07) = PH₂S = 0.2645 atm. ≅ 0.26 atm.

5 0

2 years ago

PlEasE help ASAP <br> Snskskssmskssm

salantis [7]

Answer:

message me on messenger johnpatrick so I can help you

5 0

2 years ago

WITCH IS MADE BY WEATHERING ASH SEDEMENTS MAGMA OR MINERALS

algol [13]

Magma is made from sediments

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2 years ago

What is the momentum of a 0.01 kg toy car moving at 5.0 m/s?

snow_tiger [21]

Answer: 0.05 kgm/s

Explanation:

8 0

2 years ago

Gasoline and kerosene (specific gravity 0.820) are blended to obtain a mixture with a specific gravity of 0.770. Calculate the v

Dmitrij [34]

Answer:

The volumetric ratio is 0,71

Explanation:

Let's begin with the equation:

$Db = Mb/Vb$ (1)

Where:

Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume

And we know: $Vb = Vg + Vk$ (2)

Where:

Vg: Gasoline Volume and Vk: Kerosene Volume

Therefore replacing (2) into (1):

$Db = (Mg + Mk) / (Vg + Vk)$

$Db = (Dg * Vg + Dk * Vk)/(Vg + Vk)$ (3)

Where:

Dg: Gasoline Density and Dk: Kerosene Density

The specific gravity is defined as:

$SG = Substance Density / Reference Density$

Therefore:

$Db = SGb * Dref\\Dg = SGg * Dref\\Dk = SGk * Dref$

Where:

Dref: Reference Density

SGb: Blend Specific Gravity

SGg: Gasoline Specific Gravity (which is 0.7 approximately)

SGk: Kerosene Specific Gravity

Replacing these equations into (3) we get:

$SGb * Dref = (SGg * Dref * Vg + SGk * Dref * Vk)/(Vg + Vk)$

$SGb * Dref = Dref * (SGg * Vg + SGk * Vk)/(Vg + Vk)$

$SGb = (SGg * Vg + SGk * Vk)/(Vg + Vk)$

$SGb * (Vg + Vk) = SGg * Vg + SGk * Vk$

$SGb * Vg + SGb* Vk = SGg * Vg + SGk * Vk$

Replacing with the Specific Gravity data, we obtain:

$0.77 * Vg + 0.77 * Vk = 0.7 * Vg + 0.82 * Vk$

$0.77 * Vg - 0.7 * Vg = 0.82 * Vk - 0.77 * Vk$

$0.07 * Vg = 0.05 * Vk$

$Vg/Vk = 0.05/0.07$

$Vg/Vk = 0.71$

8 0

2 years ago