What is the pressure ?

A solution is made containing 4.6 g of sodium chloride per 250g of water.

lozanna [386]

Answer:

$\large \boxed{1.81 \, \%}$

Explanation:

$\text{Mass percent} = \dfrac{\text{mass of solute} }{\text{mass of solution}} \times 100 \, \%$

Data:

Mass of NaCl = 4.6 g

Mass of water = 250 g

Calculations:

Mass of solution = mass of NaCl + mass of water = 4.6 g + 250 g = 254.6 g.

$\text{\% m/m} = \dfrac{\text{4.6 g} }{\text{254.6 g}} \times 100 \, \% = \mathbf{1.81 \, \%}\\\\\text{The percent by mass of NaCl is $\large \boxed{\mathbf{1.81 \, \%}}$}$

3 0

4 years ago

An aluminum engine block has a volume of 4.77 L and a mass of 12.88 kg. what is the density of the aluminum in grams per cubic c

Whitepunk [10]

12.88 x 1000 = 12,880 g

4.77 x 1000 = 4770 cm³

D = mass / volume

D = 12,880 / 4770

D = 2.70 g/cm³

hope this helps!

6 0

4 years ago

What do holes in volcanic rock illustrate about the conditions in which it was formed?

Sati [7]

Obliviously not all rocks have holes in them
It is called vesicular texture These refers to viscles holes pores or cavities within the igneous rock.the vesicles are the result of gas expansion(bubbles).which often occur during volcanic eruptions .

4 0

3 years ago

To identify a liquid substance, a student determined its density. Using a graduated cylinder, she measured out a 45-mL sample of

nalin [4]

Answer:

Calculated density = 0.8555g/ mL

Probable identity = Toulene

Explanation:

First off, the substance choices are;

isopropyl alcohol (density 0. 785 g/ mL)

toluene ( density 0.866g/ mL)

So upon calculation, if the density of the liquid substance is equal to either of the substances in the choice, it is that substance.

The relationship between density, mass and volume is given as;

Density = Mass / Volume

Mass = 38.5g

Volume = 45ml

Density = 38.5 / 45 = 0.8555g/ mL

Calculated density = 0.8555g/ mL

Among both substances, it is closest to toluene ( density 0.866g/ mL).

Probable identity = Toulene

8 0

3 years ago

Hclo is a weak acid (ka=4.0x10^-8) and so the salt naclo acts as a weak base. what is the ph of a solution that is 0.037 m in na

ankoles [38]

Given:

Concentration of NaClO = 0.037 M

ka (HClO) = 4.0*10⁻⁸

To determine:

The pH of the NaClO solution

Explanation:

The hydrolysis of the weak base can be represented by the ICE table shown below-

ClO- + H2O ↔ HClO + OH-

Initial 0.037M 0 0

Change -x +x +x

Equilibrium (0.037-x) x x

kb = kw/ka = [HClO][OH-]/[ClO-]

10⁻¹⁴/4*10⁻⁸ = x²/(0.037-x)

x = [OH-] = 9.62*10⁻⁵

p[OH-] = -log[OH-] = -log [9.62*10⁻⁵] = 4.02

pH = 14-p[OH-] = 14 - 4.02 = 9.98

Ans: pH of the solution is 9.98

7 0

3 years ago