12-10=2, 4/2=2, 5-2=3, 3*3=9, 4+9=13
If each shelf is to contain exactly 3 new CDs and there are only 5 shelves, only 15 can be placed in the rack. So, the answer to the second question is no. The same goes for the first question as placing 3 or fewer CDs to the shelves will make the rack insufficient for the CDs.
Answer:
z = 1 + 9y³
Step-by-step explanation:
It looks like you have ...

Because empty set has no element which automatically make it a subset of every set.
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The x intercepts are (2,0), (3,0) and (6,0)
The y intercept is (0,-36)
The graph is attached as an image.