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zloy xaker [14]
3 years ago
11

Choose the answer(s) that correctly classify the following expression x^4+400

Mathematics
1 answer:
rodikova [14]3 years ago
8 0
x^{4} + 400 =  \\  -x^{4}  = 400  \\ x = - \sqrt[4]{400}
x = - 4.47... v x = 4.47..
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6th-grade math, fill out the table! :)
Svetradugi [14.3K]

Answer:

21 wins, table is attached.

Step-by-step explanation:

The ratio of 7 wins to 2 losses is 7:2. A ratio is just saying that every time one value is increased by 7, the other is increased by 2.

So we can fill out the table, in every iteration wins increases by 7 and losses increases by 2.

When we fill this out, we find that when losses is 6, wins is 21, so when you have 2 losses you have 21 wins.

Hope this helped!

4 0
3 years ago
1. What is 35% of 80?
Alex_Xolod [135]

1. 28

2. 41.66%

3. 88%

4. 36

5. 94.5

6. 30%

7. 83.33%

8. 20%

9. 20%

10. 62.5%

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4 0
3 years ago
Which system of the inequalities is shown in the graph
jolli1 [7]

Answer:

C

Step-by-step explanation:

the equation of the parabola is : y = x² - 3x

the equation of the line is y = x + 1

and the shaded area is between those graphs

therefore y ≥ x² - 3x and y ≤ x + 1

6 0
3 years ago
Which is a factor of 20x2 + 40x + 15?<br><br> 4x + 1<br> 4x + 3<br> 2x + 3<br> x + 2
maksim [4K]
C)
2x + 3
3 0
3 years ago
what is the equation, in slope- intercept form, of the line that contains the points (-3,4) and (5,7)
gavmur [86]

Answer:

y = \frac{3}{8} x + \frac{41}{8}

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

To calculate the slope use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 4) and (x₂, y₂ ) = (5, 7)

m = \frac{7-4}{5+3} = \frac{3}{8}, hence

y = \frac{3}{8} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

using (5, 7 ), then

7 = \frac{15}{8} + c ⇒ c = 7 - \frac{15}{8} = \frac{41}{8}

y = \frac{3}{8} x + \frac{41}{8} ← equation in slope-intercept form


6 0
3 years ago
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