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Troyanec [42]
3 years ago
15

A soccer ball has a radius of 11 cm. Using 3.15

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0

Answer:

B. 3135 cm^3.

Step-by-step explanation:

I think you mean 3.14 ( for pi):

V = 4/3 pi r^3

=  3/4 * 3.14 * 11^3

= 3134.5

Goshia [24]3 years ago
7 0
U would actually have to use 3.14 not 3.15 that’s probably how u would get a better and more understanding answer.
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A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo
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Answer:

\frac{x^2}{61}-\frac{y^2}{37}  =1

Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

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(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

\frac{x^2}{61}-\frac{y^2}{37}  =1

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3 years ago
1,248 divided by 4 show the work
Tju [1.3M]
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